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3 years ago

A bowling ball and a baseball accelerate equally when falling in a vacuum because

1 answer:

4 0

Because gravity...

If you dropped a brick and a spoon, they fall down at the same pace. Weight does not make items drop faster.

Hope this helps :)

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A child is riding a merry-go-round that has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745 ra

skelet666 [1.2K]

Answer:

So the acceleration of the child will be $8.05m/sec^2$

Explanation:

We have given angular speed of the child $\omega =1.25rad/sec$

Radius r = 4.65 m

Angular acceleration $\alpha =0.745rad/sec^2$

We know that linear velocity is given by $v=\omega r=1.25\times 4.65=5.815m/sec$

We know that radial acceleration is given by $a=\frac{v^2}{r}=\frac{5.815^2}{4.65}=7.2718m/sec^2$

Tangential acceleration is given by

$a_t=\alpha r=0.745\times 4.65=3.464m/sec^$

So total acceleration will be $a=\sqrt{7.2718^2+3.464^2}=8.05m/sec^2$

7 0

3 years ago

A centrifuge accelerates uniformly from rest to 15000 rpm in 330 s . Through how many revolutions did it turn in this time?

eduard

Answer:

The number of revolutions turned by the centrifuge is 8250 revolutions.

Explanation:

Given;

number of revolution per minutes, ω = 15000 rpm

time of motion, t = 330 s = 5.5 minutes

The number of revolutions turned by the centrifuge is given by;

$N = \frac{1500 \ Rev}{minutes} *5.5 \ minutes\\\\N = 8250 \ revolutions$

Therefore, the number of revolutions turned by the centrifuge is 8250 revolutions.

4 0

3 years ago

On an aircraft carrier, a jet can be catapulted from 0 to 240

IRISSAK [1]

Answer:

m = 27752.7 [kg]

Explanation:

To solve this problem we must first use the following equation of kinematics.

$v_{f}=v_{o}+a*t$

where:

Vf = final velocity = 240 [km/h]

Vo = initial velocity = 0

a = acceleration [m/s²]

t = time = 2 [s]

But first we must convert the speed from kilometers per hour to meters per second.

$240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]$

Now replacing:

$66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]$

Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.

∑F = m*a

$925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]$

4 0

3 years ago

A hollow cylindrical (inner radius = 1.0 mm, outer radius = 3.0 mm) conductor carries a current of 80 A parallel to its axis. Th

Pavlova-9 [17]

Answer:

The magnetic field is $B = 3 mT$

Explanation:

From the question we are told that

The inner radius is $r_i = 1.00 mm =1*10^{-3} \ m$

The outer radius is $r_2 = 3.00 \ mm = 3.0 *10^{-3} \ m$

The distance from the axis of the conductor is $d =2.0 \ mm = 2.0 *10^{-3} \ m$

The current carried by the conductor is $I = 80 A$

According to Ampere's circuital law , the magnetic field at a point that is $r_3$ from the axis of the conductor

$B = \frac{\mu_oI}{2 \pi d } [\frac{d - r_1}{r_2 -r_1} ]$

Where $\mu_o$ is the permeability of free space with a value of $\mu_o = 4 \pi *10^{-7} N/A^2$

substituting values

$B = \frac{(4 \pi *10^{-7})(80)}{2 * 3.142 * 2 *10^{=3} } [\frac{(2^2 - 1 ^2 )*10^{-3}}{(3^2 - 1^2) *10^{-3}} ]$

$B = 3 mT$

5 0

4 years ago

A wire with a current of 5.2 A is at an angle of 45° relative to a magnetic field of 0.87 T. What is the force exerted on a 1.2

julsineya [31]

Answer:

F = I L X B = I L B sin theta

F = 5.2 * 1.2 * .87 sin 45 = 3.84 N in the direction of (L X B)

Note: L and B must be at right angles for F = I L B

7 0

3 years ago