A centrifuge accelerates uniformly from rest to 15000 rpm in 330 s . Through how many revolutions did it turn in this time?
1 answer:
Answer:
The number of revolutions turned by the centrifuge is 8250 revolutions.
Explanation:
Given;
number of revolution per minutes, ω = 15000 rpm
time of motion, t = 330 s = 5.5 minutes
The number of revolutions turned by the centrifuge is given by;
Therefore, the number of revolutions turned by the centrifuge is 8250 revolutions.
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Answer:
a = 17.68 m/s²
Explanation:
given,
length of the string, L = 0.8 m
angle made with vertical, θ = 61°
time to complete 1 rev, t = 1.25 s
radial acceleration = ?
first we have to calculate the radius of the circle
R = L sin θ
R = 0.8 x sin 61°
R = 0.7 m
now, calculating at the angular velocity
ω = 5.026 rad/s
now, radial acceleration
a = r ω²
a = 0.7 x 5.026²
a = 17.68 m/s²
hence, the radial acceleration of the ball is equal to 17.68 rad/s²