Write the problem as an equation:
5n <65
Solve for n by dividing both sides by 5:
n <13
Because the inequality does not contain an equal sign, n (13) is not included in the answer so there would be an open circle on the number 13
The correct answer would be A.
X=2h, y=3k
Substitute these values into equations.
y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4
2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1
We have a system of equations now.
3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1
2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0
4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0
(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0
Denominator cannot be = 0
4h(2-2h)≠0
Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1
Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.
h=3/4, then 3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then 3k = 4-4*(-1) =8 , 3k=8, k=8/3
So,
if h=3/4, then k=1/3,
and if h=-1, then k=8/3 .
Answer:
y = 3x -18 ( where y = balls sent back by Rudolf; x= balls given to Rudolf)
Step-by-step explanation:
x (Balls given) y( Balls sent back)
8 6 Δy/Δx = (27-6)/(15-8) = 3
15 27
25 57 Δy/Δx = (57-27)/(25-15) = 3
Observing the number sequence shows constant gradient and as such we can use equation of a straight line to relate the two variables.
Using the equation of a straight line we have:
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
y-6/x-8 = (27-6)/(15-8)
y-6/x-8 = 3
y-6 = 3(x-8)
y-6 = 3x - 24
y = 3x-18
It could be:
2/4
4/8
8/16
3/6
5/10
6/12
There are 2 of each angles
