Question

A single-wavelength beam of light is pointed at a dark shield with two narrow slits. As a result, an interference pattern forms in the space on the other side of the partition. The wavelength is 635 nm, and the first-order bright fringe lies at a 16.6° angle from the central maximum. What is the slit separation (in µm)?

Answer 1

Answer:

The slit separation is 2.2μm.

Explanation:

Given that,

Wavelength = 635 nm

Angle = 16.6°

Order number = 1

We need to calculate the slit position

Using formula of slit distance

$d\sin\theta= m\lambda$

$d=\dfrac{m\lambda}{\sin\theta}$

Where, $\lambda$ = wavelength

m = order number

Put the value into the formula

$d=\dfrac{1\times635\times10^{-9}}{\sin 16.6}$

$d=2.2\times10^{-6}\ m$

$d=2.2\ \mu m$

Hence, The slit separation is 2.2μm.