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Flauer [41]
2 years ago
7

You are less likely to see a total solar eclipse than a total lunar eclipse because a. the moon’s shadow covers all of Earth dur

ing a solar eclipse. b. new moon phases occur less often than full moon phases. c. only people on the daytime side of Earth can see a solar eclipse. d. the moon’s umbra only covers a small area on Earth’s surface
Physics
2 answers:
Bad White [126]2 years ago
8 0
D. Because the moons shadow during a total lunar eclipse is tinnier than the earth.
frozen [14]2 years ago
4 0

Answer:

You are less likely to see a total solar eclipse than a total lunar eclipse because

d. the moon’s umbra only covers a small area on earth’s surface.

Explanation:

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What is the current in a series circuit that has two resistors (4.0 ohms and
Maslowich
C 1.6 amps hipe this helps
6 0
3 years ago
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel
mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

\vec v_{ra} = 12 m/s North

so it will be

Let North direction is along Y axis and East direction is along X axis

\vec v_{ra} = 12\hat j

also it is given that speed of air is 6.7 m/s relative to ground

\vec v_a = 6.7 \hat i

now as we know by the concept of relative motion

\vec v_{ab} = \vec v_a - \vec v_b

\vec v_{ra} = \vec v_r  - \vec v_a

now by rearranging the terms

\vec v_r = \vec v_{ra} + \vec v_a

\vec v_r = 12 \hat j + 6.7 \hat i

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

v_r = \sqrt{12^2 + 6.7^2}

v_r = 13.7 m/s

so the net speed of Robin with respect to ground will be 13.7 m/s

7 0
3 years ago
A red train traveling at 72 km/hr and a green train traveling at 144 km/hr are headed toward one another along a straight level
Temka [501]
First, convert all the km/hr into m/s

You will get that
initial speed = 20 m/s
Initial speed of Green train = 40 m/s
Initial separation = 950 m
Velocity of approach =  20 - -40 = 60 m/s
relative acceleration = -4 m/s^2

v = u + at
0 = 60 - 4t

t = 15s

s = ut + 1/2  *at * t

s = 60 * 15  - 1/2 *4 * 225
s = 900 - 450

Separation when they stop  = 450 m

hope this helps

5 0
3 years ago
An iron vat is 11 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?
RoseWind [281]

Answer:

The change in length is 0.01056 m.

Explanation:

Given that,

Length = 11 m

Temperature = 20°C

Pressure = 1 atm

Boiling temperature = 100°C

We need to calculate the length

Using formula of change in linear expansion

\dfrac{\Delta L}{L}=\alpha_{l}\Delta T

\Delta L=L\times\alpha_{l}\times(T_{f}-T_{i})

Put the value into the formula

\Delta L=11\times12\times10^{-6}\times(100-20)

\Delta L=11\times12\times10^{-6}\times80

\Delta L=0.01056\ m

Hence, The change in length is 0.01056 m.

5 0
3 years ago
When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the ho
3241004551 [841]

Answer:

support lights as a wave

Explanation:

In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.

7 0
2 years ago
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