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Hunter-Best [27]
4 years ago
8

A rocketship is delivering payloads to the Space Station. If the rocket is accelerating at 3.2 Gs acceleration every minute (1g

is 9.8 meters per second) then how many minutes would it take to reach Earth's escape velocity 7 miles per second or 25000 mph
A Rocket travels upward to the Space station. The Rocket increases acceleration 3.2 G's a minute. how many minutes will it take for rocket to reach escape speed 7 miles per second into orbit?
Physics
1 answer:
victus00 [196]4 years ago
8 0

Answer:

356.377 min.

Explanation:

Acceleration given to the rocket = 3.2 g per minute

= 3.2 x 9.8 meters per second per minute

=31.36 meters per sec /per min

now ,25000 mph = 25000 x .44704 m / s.

= 11176 m /s

v = u + at

u = 0

t = v/a

= 11176 / 31.36 min

= 356.377 min

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Earth can be modeled with five layers based on the strengths and physical properties of the materials in them. Put the layers in
andre [41]

Answer:

Crust, Upper mantle, mantle, outer core, inner core

Explanation:

The Earth's layers have been clasified in 5 according to the materials that conform them, theri physical properties, strengths and also their state of matter. We all know how the outer layer of the Earth looks like, but if we start to dig a huge hole we are going to see different types por materials due to a change in pressure, temperature, and other factors. At the very center of the Earth there's what's called "core". The core is liquid and at extremely high temperatures. This is because of the enormous amount of pressure the rest of the Earth is putting it under. So, if we list the different layers of the Earth according to the materials they are made of, from the Earth's surface to the core, the answer is:

1) Crust (surface)

2) Upper Mantle

3) Mantle

4) Outer core

5) Inner core

In some books you may find a layer called Lithosphere. Tis layer consists not only of the crust, but also it contains the transition zone between the upper mantle and the crust.

4 0
3 years ago
In this problem, you will calculate the location of the center of mass for the Earth-Moon system, and then you will calculate th
Radda [10]

Answer:

a) Option D is correct.

The center of mass between the Eartg and the moon is inside the Earth.

Explanation:

Given,

Mass of the moon = (7.35×10²²) kg

Mass of the Earth = (6.00×10²⁴) kg

Mass of the Sun = (2.00×10³⁰) kg

Distance between the Earth and the moon = (3.80×10⁵) km

Distance between the Earth and the Sun = (1.50×10⁸) km

With the assumption that all.of the bodies being considered are on the same straight line on the x-axis,

Note that Centre of mass is given as

C.M = (Σmx)/(Σm)

For the Earth-moon system, let the earth be x=0, then the moon is at x = (3.80 × 10 5) km away.

C.M = (Σmx)/(Σm)

Σmx = (6.00×10²⁴)) × (0) + (7.35×10²²) × (3.80×10⁵) = (2.793 × 10²⁸) kg.km

Σm = (6.00×10²⁴) + (7.35×10²²) = (6.0735 × 10²⁴) kg

CM = (2.793 × 10²⁸) ÷ (6.0735 × 10²⁴)

CM = (4.60 × 10³) km = 4600 km

This means the centre of mass is 4600 km from the Earth.

The Earth's radius = 6378 km

Hence, the centre if mass is inside the Earth.

Hope this Helps!!!

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