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2 years ago

What is the energy of a 4 kg apple that is sitting on a 2 m high tree branch (use ham)

Physics

1 answer:

ziro4ka [17]2 years ago

4 0

Answer:

Explanation:

The energy is potential energy, mgh.

m = mass in kg

g = acceleration due to gravity (alot of talk about whether g is 9.8, 9.81 or 10)

h = height above your zero line (alot of times distance to the ground)

PE = mgh = 4 * 10 * 2 = 80 Nm or 80 Joules

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A wave front has the form of a

podryga [215]

Your answer is "surface of a sphere"

Hope this helps.

3 0

2 years ago

Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod

aivan3 [116]

Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force= $\frac{Gm_{1}m_{2} }{r^{2}}$

Coulombs's Law= $\frac{Kq_{1}q_{2} }{r^{2}}$

6 0

3 years ago

Read 2 more answers

Before you conduct your experiment, you need to form a hypothesis. A hypothesis is a prediction of what you think will happen in

Stolb23 [73]

Example: A apple rotting.

If I put my apple in a fridge, then it would not rot as fast because it is in a cooled area. (example)

Hope it helps! Brainiest Answer would be amazing!

5 0

3 years ago

Why is visual constancy important?

weqwewe [10]

Answer:

Explanation:

Visual constancy is a key mechanism that allows the perception to remain.the same even as images change

#CARRYONLEARNING

4 0

2 years ago

A new mechanic foolishly connects an ammeter with 0.1 Ω resistance directly across a 12-V car battery with internal resistance o

NemiM [27]

Answer:

The power dissipated by the meter is 1188W

Explanation:

Here we have a circuit constituted with a power source and two resistors in series, we can calculate the power dissipated by the meter using the following formula:

$P=I^2R_m$

We first need to fin the current going through the circuit:

$I=\frac{V}{R}\\where:\\V=voltage\\R=resistance$

$R=R_s+R_m$

because they are connected in series. So:

$I=\frac{12V}{(0.01+0.1)}=109A$

$P=(109)^2*0.1=1188W$

8 0

2 years ago