Answer:
B: Amplitude
Explanation:
When a wave travels from one medium to the other from an angle, the things that change are amplitude, wavelength, intensity and velocity.
The frequency doesn't change because the frequency depends upon the source of the wave and not the medium by which the wave is propagated.
Answer:
U = 1 / r²
Explanation:
In this exercise they do not ask for potential energy giving the expression of force, since these two quantities are related
F = - dU / dr
this derivative is a gradient, that is, a directional derivative, so we must have
dU = - F. dr
the esxresion for strength is
F = B / r³
let's replace
∫ dU = - ∫ B / r³ dr
in this case the force and the displacement are parallel, therefore the scalar product is reduced to the algebraic product
let's evaluate the integrals
U - Uo = -B (- / 2r² + 1 / 2r₀²)
To complete the calculation we must fix the energy at a point, in general the most common choice is to make the potential energy zero (Uo = 0) for when the distance is infinite (r = ∞)
U = B / 2r²
we substitute the value of B = 2
U = 1 / r²
Answer:
<u>Conservation</u>: using less water
<u>Xeriscaping</u>: replanting your yard with plants that do not require great amounts of water
<u>Desalination</u>: process of removing salt from water so that it can be used for consumption
<u>Water Budget</u>: finite amount of usable water available
<u>Potable</u>: water that is safe to use a drink
Answer:
1.8 x 10⁻³⁴ m.
Explanation:
de Broglie wavelength ( λ ) of a moving particle is given by the following expression
λ = h / momentum of the particle
In other words, de Broglie wavelength depends upon the momentum of the particle.
In the given case , particle A which is stationary collides with another particle B having some momentum . After the collision , they move together.No external force acts on them . Therefore after the collision , their momentum will be conserved. In other words , their momentum remains the same as earlier. So their de Broglie wave length will also be the same as earlier , since it depends on the momentum of the moving body.
Hence the de Broglie wavelength of the object will be 1.8 x 10⁻³⁴ m.
Answer:
The height reached by the dart in the second shot is (4 H).
Explanation:
It is given that, a spring-loaded toy dart gun is shot to a height h. In this case, all the potential energy stored in the spring is converted to potential gravitational energy at the maximum height.
........(1)
At the second shot, the spring is compressed twice as far before firing. x' = 2x
.........(2)
h is the height reached by the dart in the second shot.
Dividing equation (1) and (2) as:
h = 4H
So, the height reached by the dart in the second shot is (4 H). Hence, this is the required solution.
