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Sphinxa [80]
3 years ago
11

A ball dropped from rest falls freely until it hits the ground with a speed pf 20 m/s. The time during with the ball is in free

fall is approximately
Physics
1 answer:
saul85 [17]3 years ago
5 0

Answer:

\large \boxed{\text{2.0 s}}

Explanation:

\begin{array}{rcl}v & = & gt\\\text{20 m$\cdot$s}^{-1} & = & \text{9.807 m$\cdot$ s}^{-2} \times t\\t & = & \dfrac{20}{9.807 \text{ s}^{-1}}\\\\& = & \textbf{2.0 s}\\\end{array}\\\text{The ball is in free fall for $\large \boxed{\textbf{2.0 s}}$}

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The formula that is applicable here is E = kQ/r^2 in which the energy of attraction is proportional to the charges and inversely proportional to the square of the distance. In this case, 
kQ1/(r1)^2 = kQ2/(r2)^2  r1=l/3, r2=2l/3solve Q1/Q2
kQ1/(l/3)^2 = kQ2/(2l/3)^2  kQ1/(l^2/9) = kQ2/(4l^2/9)Q1/Q2 =   1/4
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2 years ago
Relative formula mass of CuCO3
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Molecular weight calculation:

63.546 + 12.0107 + 15.9994*3

Percent composition by element

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1 year ago
Find the magnitude of the sum
shusha [124]

Answer:

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

Explanation:

<u>Sum of Vectors in the Plane</u>

Given two vectors

\displaystyle \vec{v_1}\ ,\ \vec{v_2}

They can be expressed in their rectangular components as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The sum of both vectors can be done by adding individually its components

\displaystyle \vec{v_1}+\vec{v_2}=

If the vectors are given as a magnitude and an angle (M\ ,\ \theta ), each component can be found as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The first vector has a magnitude of 3.14 m and an angle of 30°, so

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=

The second vector has a magnitude of 2.71 m and an angle of -60°, so

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=

The sum of the vectors is

\displaystyle \vec{v_1}+\vec{v_2}=

\displaystyle \vec{v_1}-\vec{v_2}=

Finally, we compute the magnitude of the sum

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{(4.08)^2+(-0.78)^2}

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{17.25}

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

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3 years ago
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