The valence electrons of metals are weakly attracted to the parent nuclei, so the electrons break free and float. The moving electrons form a electron <u>negative</u> blanket that binds the atomic <u>positive</u> nuclei together, forming a metallic bond.
So the answers are <u>{ Negative }</u> and <u>{ Positive }.</u>
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You can only determine the speed since the only info we know is how much you ran in how long of a time.
Answer:
Both objects will undergo the same change in velocity
Explanation:
m = Mass of the Earth = 5.972 × 10²⁴ kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Earth = 6371000 m
m = Mass of object
Any object which is falling has only the acceleration due to gravity.
![ma=\dfrac{GMm}{r^2}\\\Rightarrow a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{(6.371\times 10^6)^2}\\\Rightarrow a=9.81364\ m/s^2](https://tex.z-dn.net/?f=ma%3D%5Cdfrac%7BGMm%7D%7Br%5E2%7D%5C%5C%5CRightarrow%20a%3D%5Cdfrac%7BGM%7D%7Br%5E2%7D%5C%5C%5CRightarrow%20a%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%205.972%5Ctimes%2010%5E%7B24%7D%7D%7B%286.371%5Ctimes%2010%5E6%29%5E2%7D%5C%5C%5CRightarrow%20a%3D9.81364%5C%20m%2Fs%5E2)
The acceleration due to gravity on Earth is 9.81364 m/s²
So, the speeds of the objects will change at an equal rate of 9.81364 m/s² but the change will be negative when an object is thrown up.
Hence, both objects will undergo the same change in velocity.
Answer:
R=3818Km
Explanation:
Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.
Since you travel 2π radians in 24H, the angle can be calculated as:
t being expressed in hours.
![\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cfrac%7B2%2A%5Cpi%20%2A11.9s%2A1H%2F3600s%7D%7B24H%7D%3D0.000865rad)
From the triangle formed by A,B and the center of the planet, we know that:
Solving for r, we get:
![r=\frac{H*cos(\alpha) }{1-cos(\alpha) } =3818Km](https://tex.z-dn.net/?f=r%3D%5Cfrac%7BH%2Acos%28%5Calpha%29%20%7D%7B1-cos%28%5Calpha%29%20%7D%20%3D3818Km)