Explanation:
The Net Force of the object can be written by:
Fnet = ma
where m is the mass of the object in <em>kg</em>
a is the acceleration of the object in <em>m/s^2</em>
Hence by applying the formula we get:
Fnet = (2.0)(3.0)
= 6N
We also know that Net force is also the sum of all forces acting on an object. In this case Friction and the Pushing Force is acting on the object. Hence we can write that:
Fnet = Pushing Force + (-Friction)
6N = 6N - Friction
Friction = 0N
Hence the<u> </u><u>f</u><u>orce of friction is 0N.</u>
Answer:
See explanation
Explanation:
We have a mass 
revolving around an axis with an angular speed 
, the distance from the axis is 
. We are given:
![\omega = 10 [rad/s]\\r=0.5 [m]\\m=13[Kg]](https://tex.z-dn.net/?f=%5Comega%20%3D%2010%20%5Brad%2Fs%5D%5C%5Cr%3D0.5%20%5Bm%5D%5C%5Cm%3D13%5BKg%5D)
and also the formula which states that the kinetic rotational energy of a body is:
.
Now we use the kinetic energy formula
where 
is the tangential velocity of the particle. Tangential velocity is related to angular velocity by:
After replacing in the previous equation we get:
now we have the following:
therefore:
then the moment of inertia will be:
![I = 13*(0.5)^2=3.25 [Kg*m^2]](https://tex.z-dn.net/?f=I%20%3D%2013%2A%280.5%29%5E2%3D3.25%20%5BKg%2Am%5E2%5D)
Answer:
I believe the answer is A and D.
I am unsure of C.
Answer:
21.4 mph
Explanation:
Circumference of tire in FEET = pi * d = pi * 1 ft = pi feet
pi feet x 600 rot/min * 60 min /hr * 1 mile / 5280 feet = 21.4 mph
