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fgiga [73]
3 years ago
11

Which one of the following is not a compound?

Chemistry
1 answer:
Studentka2010 [4]3 years ago
3 0
Cookies, they are more than a compound

3asy
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A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 385.mg of oxalic acid H2
Vlada [557]

Answer:

The molarity of the sodium hydroxide solution is 0.0692 M

Explanation:

<u>Step 1: </u>Data given

Mass of H2C2O4 = 385 mg = 0.385 grams

volume = 250 mL = 0.250 L

Volume of NaOH = 123.7 mL = 0.1237 L

Molar mass H2C2O4 = 90.03 g/mol

<u>Step 2</u>: The balanced equation

2NaOH + H2C2O4 → Na2C2O4 + 2H2O

<u>Step 3:</u> Calculate moles H2C2O4

Moles H2C2O4 = mass H2C2O4 / molar mass H2C2O4

Moles H2C2O4 = 0.385 grams / 90.03 g/mol

Moles H2C2O4 = 0.00428 moles

<u>Step 4: </u>Calculate molarity of H2C2O4

Molarity H2C2O4 = moles / volume

Molarity H2C2O4 = 0.00428 moles / 0.250 L

Molarity H2C2O4 = 0.01712 M

<u>Step 5:</u> Calculate molarity of NaOH

2*Ca*Va = n*Cb*Vb

⇒ with Ca = Molarity of H2C2O4 = 0.01712 M

⇒ Va = volume of H2C2O4 = 0.250 L

⇒Cb = molarity of NaOH = TO BE DETERMINED

⇒ Vb = volume of NaOH = 0.1237 L

Cb = (2*0.01712*0.250)/0.1237

Cb = 0.0691 M

The molarity of the sodium hydroxide solution is 0.0692 M

4 0
3 years ago
When objects touch each other, charge can be transferred by
Dovator [93]

Answer:

friction

Explanation:

electrons from one uncharged object to another uncharged object by rubbing. When two uncharged objects rub together, some electrons from one object can move onto the other object. hope this is your right

and not just a riddle

7 0
3 years ago
240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an
ivolga24 [154]
The answer for this would be 69.6
3 0
3 years ago
Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m
faust18 [17]

Answer:

56°

Explanation:

First calculate a:

a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}

The interplanar spacing can be calculated from:

d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}

The diffraction angle is determined from:

\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476

Solve for \theta

\theta=\sin ^{-1}(0.476)=28^{\circ}

The diffraction angle is:

2 \theta=2\left(28^{\circ}\right)=56^{\circ}

4 0
3 years ago
Select the keyword or phrase that will best complete each sentence.
pishuonlain [190]

Answer:

1) acetylide

2) enol

3) aldehydes

4) tautomers

5) alkynes

6) Hydroboration

7) Keto

8) methyl ketones

Explanation:

Acetylide anions (R-C≡C^-) is a strong nucleophile. Being a strong nucleophile, we can use it to open up an epoxide ring by SN2 mechanism. The attack of the acetylide ion occurs from the backside of the epoxide ring. It must attack at the less substituted side of the epoxide.

Oxomercuration of alkynes and hydroboration of alkynes are similar reactions in that they both yield carbonyl compounds that often exhibit keto-enol tautomerism.

The equilibrium position may lie towards the Keto form of the compound. Usually, if terminal alkynes are used, the product of the reaction is a methyl ketone.

3 0
3 years ago
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