Answer:
Both answer choice 2 and answer choice 3 are correct choices.
Explanation:
Biotic factors are living components in an ecosystem. They are living organisms which affect another living component in an ecosystem.
Antibiotic factors are non living components of an ecosystem. They are chemicals which affect living organisms.
The choice 2 is correct. The seeds spread out by mice is a biotic factor interacting with an antibiotic factor
Choice 3 is correct. The seeds in the soil grow into new trees are biotic factors interacting with an antibiotic factor
Answer:
The molar mass of Mg(NO₃)₂, 148.3 g/mol.
Explanation:
Step 1: Given data
- Mass of Mg(NO₃)₂ (solute): 42.0 g
- Volume of solution: 259 mL = 0.259 L
Step 2: Calculate the moles of solute
To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.
42.0 g × 1 mol/148.3 g = 0.283 mol
Step 3: Calculate the molarity of the solution
M = moles of solute / liters of solution
M = 0.283 mol / 0.259 L
M = 1.09 M
Answer:
See explanation
Explanation:
I know that we usually associate the sp3 hybridization to the tetrahedral shape. This is common in molecules such as CH4. So it may sound somewhat strange that NH3 molecule has an sp3 hybridized nitrogen atom and a trigonal pyramidal geometry.
Let us recall that the central nitrogen atom in NH3 has a lone pair of electrons. These lone pairs causes more repulsion than bond pairs. As a result of the presence of this lone pair, the bond angle in the NH3 molecule is distorted away from the expected 109.7 degrees in tetrahedral geometry and the bonding groups are now arranged in a trigonal pyramidal geometry(with bond angle less than 109.7 degrees) to minimize electron pair repulsions.
Molarity is defined as the number of moles of solute in 1 L of solution
the mass of Ca(NO₃)₂ present - 8.50 g
therefore number of moles of Ca(NO₃)₂ - 8.50 g / 164 g/mol = 0.0518 mol
the volume of solution prepared is 755 mL
therefore if there are 0.0518 mol in 755 mL
then in 1000 mL the number of moles - 0.0518 mol / 0.755 L
molarity is therefore - 0.0686 M
