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Llana [10]
3 years ago
5

The isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it. what isotope is created? loo

k up the peridoic table to find which element has 31 protons.
Gallium-72
yttrium-41
yttrium-72
Gallium-41
Chemistry
2 answers:
Fed [463]3 years ago
5 0
It is gallium look it up its what google says
Rashid [163]3 years ago
3 0

Answer: Gallium-72

Explanation:

Atomic number is defined as the number of protons or number of electrons that are present in an atom. It is characteristic of an element.

Atomic number = Number of electrons = Number of protons = 31

Thus the element with atomic number of 31 is Gallium.

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

There were 39 neutrons and then 2 more were added , thus there are 39+2 = 41 neutrons

Thus mass number = 31 + 41 = 72

Thus the element will be gallium with 72 mass number.

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The one that has a higher entropy for the reaction is products.

<h3>What is entropy?</h3>

Entropy is a measureable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty. It is the measurement of the amount of thermal energy per unit of temperature in a system that cannot be used for productive work. It is a measure of a system's molecular disorder or unpredictability since work is produced by organized molecular motion.

It should bm be noted that the entropy of gas is more than entropy of aqueous which is more than the entropy of liquid and the entropy of solid.

On the product side there are more gas than the reactant side. Therefore, product has more entropy.

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How many isomers does propane have?<br> 01<br> 02<br> 03<br> 05
Irina18 [472]

Answer:

A.) 1

Explanation:

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5 0
2 years ago
PLEASE ANSWER I AM BEGGING
TiliK225 [7]

Taking into account the definition of dilution:

  • you have to use 8.23 mL of a stock solution of 7.00 M HNO₃ to prepare 0.120 L of 0.480 M HNO₃.
  • If you dilute 20.0 mL of the stock solution to a final volume of 0.270 L , the concentration of the diluted solution is 0.518 M.

<h3>Dilution</h3>

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

<h3>Volume of stock solution</h3>

In this case, you know:

  • Ci= 7 M
  • Vi= ?
  • Cf= 0.480 M
  • Vf= 0.120 L

Replacing in the definition of dilution:

7 M× Vi= 0.480 M× 0.120 L

Solving:

Vi= (0.480 M× 0.120 L)÷ 7 M

<u><em>Vi= 0.00823 L= 8.23 mL</em></u> (being 1 L= 1000 mL)

Finally, you will need 8.23 mL of the stock solution.

<h3>Concentration of the diluted solution</h3>

In this case, you know:

  • Ci= 7 M assuming the stock solution is 7.00 M HNO₃
  • Vi= 20 mL= 0.02 L
  • Cf= ?
  • Vf= 0.270 L

Replacing in the definition of dilution:

7 M× 0.02 L= Cf× 0.270 L

Solving:

(7 M× 0.02 L)÷ 0.270 L= Cf

<u><em>0.518 M= Cf</em></u>

Finally, the concentration is 0.518 M.

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