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Snezhnost [94]
3 years ago
10

How many moles of water are in 1.23x10^18 water molecules

Chemistry
2 answers:
Olegator [25]3 years ago
8 0

Answer:

There are 2.04*10⁻⁶ moles of water in 1.23*10¹⁸ water molecules

Explanation:

Avogadro Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.

In this case you know that there are 1.23*10¹⁸ molecules of there. So, knowing Avogadro's number, a rule of three applies as follows: if 6.023*10²³ molecules represent 1 mole of the compound, 1.23*10¹⁸ molecules in how many moles will they be?

moles=\frac{1.23*10^{18} molecules*1mole}{6.023*10^{23}molecules }

moles=2.04*10⁻⁶

<u><em>There are 2.04*10⁻⁶ moles of water in 1.23*10¹⁸ water molecules</em></u>

Harlamova29_29 [7]3 years ago
6 0

By 1.23 x 1024 you mean 10 to the power of 24 molecules? If so all you need to do is divide the number of molecules you have by Avagadros number, 6.022 x 10^23. This will give you the mols of water, or the mols of anything, since there is always 6.022 x 10^23 molecules in 1 mol of substance.


1.23x10^24 atoms/6.022x10^23 atom/mol = 2.04 mol H20


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In basic terms only some substances can make a solutions others are refered to as insoluble as they can't be seperated in water or another solvent. In actuality however all ionic compounds (compounds that are composed of ions) are at least somewhat soluble, but don't dissociate well at all in some solvents. 

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3 years ago
A gas occupies 3.5L at 2.5 atm of pressure. What is the volume at 787 torr at the same temperature?
Kitty [74]

Answer: 8.45 L

Explanation:

Given that,

Initial volume (V1) = 3.5L

Initial pressure (P1) = 2.5 atm

[Since final pressure is given in torr, convert 2.5 atm to torr

If 1 atm = 760 torr

2.5 atm = 2.5 x 760 = 1900 torr

Final volume (V2) = ?

Final pressure (P2) = 787 torr

Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

P1V1 = P2V2

3.5L x 1900 torr = 787 torr x V2

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Divide both sides by 787 torr

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5 0
3 years ago
) Do you think the pH of 1,0 M tri-methyl ammonium (CH3)3NH+, pKa = 9.80, will be higher or lower than that of 1.0 M phenol, C6H
Elanso [62]

Answer:

1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).

2. The difference in pH values is 4.95.

Explanation:

1. The pH of a compound can be found using the following equation:

pH = -log([H_{3}O^{+}])

First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.

<u>Trimethyl ammonium</u>:

We can calculate [H₃O⁺] using the Ka as follows:

(CH₃)₃NH⁺ + H₂O  →  (CH₃)₃N + H₃O⁺    

1.0 - x                               x           x  

Ka = \frac{[(CH_{3})_{3}N][H_{3}O^{+}]}{[(CH_{3})_{3}NH^{+}]}

10^{-pKa} = \frac{x*x}{1.0 - x}

10^{-9.80}(1.0 - x) - x^{2} = 0    

By solving the above equation for x we have:  

x = 0.097 = [H₃O⁺]

pH = -log([H_{3}O^{+}]) = -log(0.097) = 1.01                                      

<u>Phenol</u>:

C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺

1.0 - x                        x             x

Ka = \frac{[C_{6}H_{5}O^{-}][H_{3}O^{+}]}{[C_{6}H_{5}OH]}

10^{-10} = \frac{x^{2}}{1.0 - x}

1.0 \cdot 10^{-10}(1.0 - x) - x^{2} = 0

Solving the above equation for x we have:

x = 9.96x10⁻⁶ = [H₃O⁺]

pH = -log([H_{3}O^{+}]) = -log(9.99 \cdot 10^{-6}) = 5.00

Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.

2. The difference in pH values for the two acids is:

\Delta pH = pH_{C_{6}H_{5}OH} - pH_{(CH_{3})_{3}NH^{+}} = 5.00 - 1.01 = 4.95

Therefore, the difference in pH values is 4.95.

I hope it helps you!

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