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Klio2033 [76]
3 years ago
13

Can enter through any cavity lined with mucus membranes

Physics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

mucus

Explanation:

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If you are using a wrench to loosen a very stubborn nut, you can make the job easier by using a "cheater pipe." This is a piece
pentagon [3]

Answer:

Explained

Explanation:

The cheater pipe extends the wrench in  radial direction, providing a larger momentum for the force you exert.

For a given force the torque exerted with the cheater pipe is larger.

Mathematically we can write that

τ = r×F and τ'= r'×F

now since r'> r

⇒ F'>F

5 0
3 years ago
Read 2 more answers
How is the voltage V across the resistor related to the current I and the resistance R of the resistor? (Use I for current and R
VladimirAG [237]

Answer:

This relationship is explained by Ohm's law

Explanation:

Ohm's law states that the current flowing through a circuit or a resistor is directly proportional to the voltage across the resistor and inversely proportional to the resistance. Where current is i, voltage is v and resistance is r, Ohm's law can be represented mathematically as

V= IR

8 0
3 years ago
Which is not true about the pH scale?
pochemuha

Answer:

The pH scale was invented by Svante Arrhenius is false.

Explanation :

because the pH scale was invented by Soren Sorensen

4 0
3 years ago
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(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylind
Vilka [71]
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
F_f = \mu N
where \mu is the coefficient of friction, while N is the normal force. So we have:
F=\mu N
since we know that F=300 N and \mu=0.3, we can find N, the magnitude of the normal force:
N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is \mu=0.03 due to the presence of the oil. Therefore, we have:
N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N
8 0
3 years ago
A child and sled with a combined mass of 50.0 kg slide down a frictionless slope. if the sled starts from rest and has a speed o
Furkat [3]
            <span> Using conservation of energy

Potential Energy (Before) = Kinetic Energy (After)

mgh = 0.5mv^2

divide both sides by m

gh = 0.5v^2

h = (0.5V^2)/g

h = (0.5*2.2^2)/9.81

h = 0.25m

</span>
4 0
3 years ago
Read 2 more answers
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