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2 years ago

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Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first obj

ect. they both slide up the same frictionless inclined plane. which object rises to a greater height?

1 answer:

Zarrin [17]2 years ago

5 0

first object gors highest

second object goes lowest.

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The bellow of a territorial bull hippopotamus is measured at 100 dB above the threshold of hearing. What is the sound intensity?

Dmitriy789 [7]

Answer:

Explanation:

The hippopotamus hearing threshold is 100dB

β = 100 dB

The threshold of human hearing is Io = 1 × 10^-12 W/m²

The sound intensity level is given as

β = 10•Log(I / Io)

100 = 10•Log(I / Io)

Divided Both sides by 10

100 / 10 = Log(I / Io)

10 = Log(I / Io)

Take inverse Logarithm ( antilog) of both sides

10^10 = 10^[Log(I / Io)]

10^10 = I / Io

Then,

I = 10^10 × Io

I = 10^10 × 1 × 10^-12

I = 1 × 10^-2 W/m²

I = 0.01 W/m²

The sound intensity is 0.01 W/m²

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2 years ago

The table below shows some common animals and their hearing range in Hertz (Hz). Animal Hearing Range in Rate of Vibrations per

kap26 [50]

Answer:

D

Explanation:

If you list and compare, the elephants hearing range is the closest to a humans.

Humans: 20-20,000

Elephant: 16-12,000

While the others are either too much more or less than a humans.

Bat: 2,000-110,000

Dolphin: 90-105,000

Chicken: 125-2,000

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2 years ago

Which of the following are ways the rising human population can lower their impact on the Earth's spheres and climate change? Se

Tju [1.3M]

a and c because its right im out of college

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3 years ago

Which of the following cannot be determined by analyzing the periodic table?

dybincka [34]

Your answer is C) The year the element was discovered :)

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2 years ago

Read 2 more answers

During a braking test, a car is brought to rest beginning from an initial speed of 60 mi/hr in a distance of 120 ft. With the sa

maw [93]

Answer:

Explanation:

Given

Initial speed $u=60\ mi/hr\approx 88\ ft/s$

distance traveled before coming to rest $d_1=120\ ft$

using equation of motion

$v^2-u^2=2as$

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

$0-(88)^2=2\times a\times 120---1$

for $u_2=80\ mi/hr\approx 117.33\ ft/s$

using same relation we get

$0-(117.33)^2=2\times a\times (d_2)----2$

divide 1 and 2 we get

$(\frac{88}{117.33})^2=\frac{120}{d_2}$

$d_2=213.32\ ft$

So a distance if 213.32 ft is required to stop the vehicle with 80 mph speed

8 0

2 years ago