The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.
<h3>
Linear expansivity </h3>
The temperature to which it must be heated in order to fit the shaft is calculated as follows;
where;
- ΔT is change in temperature
- ΔL is change in length = 50.04 mm - 50 mm = 0.04 mm
- α is coefficient of linear expansion
- L is original length
ΔT = (0.04)/(50 x 15 x 10⁻⁶)
ΔT = 53.3 ⁰C
<h3>Final temperature</h3>
T₂ - T₁ = ΔT
T₂ = ΔT + T₁
where;
- T₂ is final temperature
- T₁ is initial temperature
T₂ = 53.3 + 20
T₂ = 73.33 ⁰C
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At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.
As a result, the manatee now becomes negatively buoyant and must rise to compensate.
<h3>What does it mean when something has neutral buoyancy?</h3>
When something has neutral buoyancy, it is not affected by the weight of anything above or below it.
This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.
Examples of things with neutral buoyancy include air balloons and swimming caps.
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Answer:
Yes! im not sure if this is correct :)
Explanation:
Answer:
approximately 1.625 m/s , about 16.6% that on Earth's surface or 0.166 ɡ. Over the entire surface, the variation in gravitational acceleration is about 0.0253 m/s.
Answer:
D. The friction force increases by 9600 N.
Explanation:
Frictional force is directly proportional to kinetic coefient of friction.