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swat32
3 years ago
6

In deriving the axial electric field for the ring-shaped charge distribution and the electric field from a long line of charge,

the component perpendicular to the resulting field is zero because of what physical property? In deriving the axial electric field for the ring-shaped charge distribution and the electric field from a long line of charge, the component perpendicular to the resulting field is zero because of what physical property? positive and negative charges cancel symmetry only net charge is important superposition integration
Physics
1 answer:
Rudiy273 years ago
5 0

Answer:

d)symmetry

Explanation:

Here is the complete question

In deriving the axial electric field for the ring-shaped charge distribution and the electric field from a long line of charge, the component perpendicular to the resulting field is zero because of what physical property? Answer a)integration b)superposition c)only net charge is important d)symmetry e) positive and negative charges cancel

Solution

The perpendicular components of the resulting electric field is zero because of symmetry since the charge is evenly distributed around the ring or line of charge. At one point, there is an electric field dE due to a small charge element dq and a corresponding electric field dE' due to a small charge element dq' opposite to dq.

Since the charges are symmetrical about the center, the horizontal (or perpendicular) components of the electric fields would cancel out causing the horizontal component of the resulting electric field to be zero.

So, the perpendicular component of the resulting electric field is zero due to symmetry.

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4 0
2 years ago
A box is pulled with a horizontal force of 500N and moves 5m what is work done
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The answer to the question is shown below:

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4 0
4 years ago
A 2kg bowling ball is 2.5 meter off the ground on a post when it falls. Just before it reaches the ground, it is traveling 7m/s.
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7 0
4 years ago
An electron enters the gap between the plates of a capacitor at the center of the gap traveling parallel to theplates at 2.0 x 1
Svetlanka [38]

Answer:

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Explanation:

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4 0
3 years ago
The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is three times as massive as planet 1 and orbit
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3 0
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