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alexandr402 [8]
3 years ago
6

Compute the resistance in ohms of a copper block 5.0 cm long and 0.10 cm2 in cross-sectional area. (ρ = 1.77 × 10-6 ohm-cm)

Physics
1 answer:
soldier1979 [14.2K]3 years ago
4 0
R=ρ l/a
l=5 cm
a=0.10 cm²
ρ=1.77×10∧-6 Ωcm
R=(1.77×10∧-6) ×5/0.10
  =8.85 ×10∧-5 Ω

resistance is directly proportional to length and inversly proportional to area of cross section is given by above equation 
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Given:

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density of air at inlet, \rho_{b} = 1.05 kg/m_{3}

Solution:

Now,

\dot{m} = \dot{m_{a}} = \dot{m_{b}}

\rho_{a} A v_{a} = \rho _{b} Av_{b}                        (1)

where

A = Area of cross section

v_{a} = velocity of air at inlet

v_{b} = velocity of air at outlet

Now, using eqn (1), we get:

\frac{v_{b}}{v_{a}} = \frac{\rho_{a}}{\rho_{b}}

\frac{v_{b}}{v_{a}} = \frac{1.20}{1.05} = 1.14

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which is 14% more

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5 0
3 years ago
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ikadub [295]

Answer:

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Explanation:

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3 years ago
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8 0
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1
shepuryov [24]

Answer:

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So 1000x100x2 gives us 200000J.

Thank you

If you have any questions please feel free to contact me.

I will contact u through the comments.

❤️❤️With love,

Joel X grader

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lilavasa [31]

Answer:

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