The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.
Its speed decreases, its wavelength increases, and its frequency Remains the Same.
Answer:
4cm
Explanation:
Magnification of the virtual image
= image distance / object distance
Given
Image distance = 60.0cm
Object distance = 15.0cm
Therefore,
Magnification = 60.0/15.0
= 4 cm
Draw a freebody diagram, it will explain it really well
the boat is floating on top of the water, which means that the net acceleration in the y direction must be zero
the boat is not sinking (dominant downwards acceleration/force)
the boat is not flying (dominant upward acceleration/force)
that measn

now, if you drew the FBD, you only have 2 forces acting on the boat.
the upward bouyancy force on the boat and the downward force due to weight

since the net force is equal to zero

and thus
Answer:
a. a= 1.029 ms⁻²
b. S=25.89 m
Explanation:
given
initial speed is u = 7.30 m/sec
final speed is v = 0 m/sec
mu_k = 0.105
kinetic frictional force is Fk = mu_k×m×g
mu_k×m×g = m×a
m cancels
mu_k×g = a
deccelaration a = mu_k×g = 0.105×9.8 =1.029 ms⁻²
b) using v²-u² = 2aS
0²-7.3² = -2×1.029×S
53.29=2.058×S
S = 53.29/2.058
S=25.89 m