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3 years ago

13

5. For the speaker in this circuit, the voltage across it is always proportional to the current through it. Find the maximum amo

unt of power that the circuit can deliver to the speaker.

1 answer:

rosijanka [135]3 years ago

4 0

Answer:

speaker64

--------

34x

Explanation:

64-34

x

speaker

4

2

4

788

- circuit

voltage

100000

x.34

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Find the sum of the vectors: 40m/s2 Northeast, 10 m/s2 Northeast

podryga [215]

Answer:

Explanation:

Since both vectors are pointing on the same direction (Northeast), the sum of them will point in that same direction, and its magnitud will be the sum of the magnitudes of each vector (40m/s2+10m/s2). This problem is just a problem in one dimension. The sum of the vectors is then 50m/s2 Northeast.

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A moving particle encounters an external electric field that decreases its kinetic energy from 9970 eV to 6340 eV as the particl

marusya05 [52]

Answer:

q = -1.61x10⁻¹⁷ C

Explanation:

The charge of the particle can be found using the definition of the work done by electric force:

$W = -q\Delta V$ (1)

<u>Where</u>:

q: is the charge

ΔV: is the difference in electric potential

The work is also equal to:

$W = E_{p_{A}} - E_{p_{B}}$ (2)

<u>Where</u>:

$E_{p_{A}}$ and $E_{p_{B}}$ are the electric potential energy of the points A and B, respectively.

Now, by conservation of energy we have:

$K_{A} + E_{p_{A}} = K_{B} + E_{p_{B}}$ (3)

<u>Where</u>:

$K_{A}$ and $K_{B}$ are the kinetic energy of the points A and B, respectively.

Rearranging equation (3):

$K_{B} - K_{A} = E_{p_{A}} - E_{p_{B}}$

$K_{B} - K_{A} = W$

$K_{B} - K_{A} = -q\Delta V$

Solving the above equation for q:

$q = -\frac{K_{B} - K_{A}}{V_{B} - V_{A}} = -\frac{6340 eV - 9970 eV}{19.0 V - 55.0 V} = -100.83 e \cdot \frac{1.6 \cdot 10^{-19} C}{1 e} = -1.61 \cdot 10^{-17} C$

Therefore, the charge of the particle is -1.61x10⁻¹⁷ C.

I hope it helps you!

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zepelin [54]

Answer:

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Explanation:

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klasskru [66]

Answer:

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According to Newton's third law of motion, it states that for every action, there is an equal and opposite reaction. This implies that when you exert a force of 400 N on an object, it will react by giving an equal -400 N to counter the oncoming force. Notice that the equal force is negative to mean it's opposite of the action.

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