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igomit [66]
3 years ago
10

Which statement best describes what is taking place? Copper is being oxidized. Copper is being reduced. Copper is losing electro

ns. Copper is a reducing agent.
Chemistry
1 answer:
Rasek [7]3 years ago
3 0

Answer:

copper is being reduced

Explanation: I got 100% on the quiz good luck this class is hard lol

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Hello! I just need a little bit of help. I'm supposed to design an experiment on how reaction rates are determined and affected
alexandr1967 [171]
  1. Get 3 cups of water at the exact same temperature, using the thermometer to check.
  2. Label the cups as ‘whole’, ‘pieces’, and ‘crushed’
  3. Next, get something to dissolve, in this case, polident. Take one of the polident tablets and break it into 4 pieces, and set it aside.
  4. Take another polident tablet and this time put it into a different cup, and crush it. Set it aside.
  5. Keep the last tablet whole.
  6. Set up your stopwatch and drop the polident tablet that is whole in the cup labeled ‘whole’, starting the stopwatch at the same time.
  7. Watch the cup and see when the tablet is fully dissolved, then stop the stopwatch.
  8. Record the time in the table.
  9. Repeat steps 6-8 for both the ‘pieces’ and ‘crushed’ tablets.

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!

Stay Brainy!

−xXheyoXx

3 0
2 years ago
A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution
madam [21]

<u>Answer:</u> The initial pH of the HCl solution is 3

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL

Putting values in above equation, we get:

1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M

1 mole of HCl produces 1 mole of H^+ ions and 1 mole of Cl^- ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.001M

Putting values in above equation, we get:

pH=-\log (0.001)\\\\pH=3

Hence, the initial pH of the HCl solution is 3

6 0
3 years ago
Light bending as it passes through a rain drop is an example of Transmission Diffraction Refraction Reflection
Yuliya22 [10]
The answer would be the third one listed, Refraction
4 0
2 years ago
Question 7: *
Otrada [13]

Answer:

2

Explanation:

Thermal, chemical and electromagnetic is the right answer

6 0
2 years ago
ammonia gas reacts with oxygen gas, o2(g), to produce nitrogen dioxide and water. when 28.5 g of ammonia gas reacts with 83.4 g
jolli1 [7]

The percent yield of the reaction between ammonia gas with oxygen gas is 90.52%.

A chemical reaction between ammonia gas (NH3) with oxygen gas (O2)

NH₃ + O₂ → NO₂ + H₂O

The balanced reaction 4NH₃ + 7O₂ → 4NO₂ + 6H₂O

Calculate the number of moles from the reactant

  • Ammonia gas
    Molar mass N = 14 gr/mol
    Molar mass H = 1 gr/mol
    Molar mass NH₃ = 14 + (3 × 1) = 14 + 3 = 17 gr/mol
    mass = 28.5 grams
    n = m ÷ molar mass = 28.5 ÷ 17 = 1.68 mol
  • Oxygen gas
    Molar mass O = 16 gr/mol
    Molar mass O₂ = 16 × 2 = 32 gr/mol
    mass = 83.4 grams
    n = m ÷ molar mass = 83.4 ÷ 32 = 2.61 mol
  • n O₂ ÷ coefficient O₂ = 2.61 ÷ 7 = 0.37
    n NH₃ ÷ coefficient NH₃ = 1.68 ÷ 4 = 0.42
    0.42 > 0.37 it means that the ammonia gas is in excess and the O₂ is limiting.

According to stoichiometry, the number of moles NO₂ with the number of moles O₂ has the ratio with the coefficient in reaction.

  • Theoretically the number moles of NO₂
    n O₂ : n NO₂ = 7 : 4
    2.61 : n NO₂ = 7 : 4
    n NO₂ = 4 x 2.61 : 7 = 1.49 mol
  • The actual number of moles NO₂
    Molar mas NO₂ = 14 + (16 × 2) = 14 + 32 = 46 gr/mol
    n NO₂ = m ÷ molar mass = 61.9 ÷ 46 = 1.35 mol

The percent yield NO₂ is the ratio of the actual number of moles NO₂ with the theoretical number of moles NO₂ times 100%.

P = (1.35 ÷ 1.49) × 100%

P = 0.9052 × 100%

P = 90.52%

Learn more about stoichiometry here: brainly.com/question/13691565

#SPJ4

7 0
1 year ago
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