Answer:
Gamma rays
Explanation:
Have the highest energies. The shortest wavelengths, and the highest frequencies.
The dolphin would send an underwater message because the water is denser than air and therefore the sound would be louder and would travel faster. The denser the object the faster the sound travels.
Answer:
The solution was to implement an absolute magnitude scale to provide a reference between stars. To do so, astronomers calculate the brightness of stars as they would appear if it were 32.6 light-years, or 10 parsecs from Earth.
Explanation:
So simply it to 120m/m for 120 minutes. So then you multiply 120x120 and that equals 14,400
Answer:
![\dfrac{d\theta}{dt}=0.038\ rad/s](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5Ctheta%7D%7Bdt%7D%3D0.038%5C%20rad%2Fs)
Explanation:
Given that
![\dfrac{dx}{dt}= -1\ m/s](https://tex.z-dn.net/?f=%5Cdfrac%7Bdx%7D%7Bdt%7D%3D%20-1%5C%20m%2Fs)
From the diagram
![tan\theta=\dfrac{21}{x}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cdfrac%7B21%7D%7Bx%7D)
By differentiating with time t
![sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}](https://tex.z-dn.net/?f=sec%5E2%5Ctheta%20%5Cdfrac%7Bd%5Ctheta%7D%7Bdt%7D%3D-%5Cdfrac%7B21%7D%7Bx%5E2%7D%5Cdfrac%7Bdx%7D%7Bdt%7D)
When x= 10 m
![tan\theta=\dfrac{21}{10}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cdfrac%7B21%7D%7B10%7D)
θ = 64.53°
Now by putting the value in equation
![sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}](https://tex.z-dn.net/?f=sec%5E2%5Ctheta%20%5Cdfrac%7Bd%5Ctheta%7D%7Bdt%7D%3D-%5Cdfrac%7B21%7D%7Bx%5E2%7D%5Cdfrac%7Bdx%7D%7Bdt%7D)
![sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)](https://tex.z-dn.net/?f=sec%5E264.53%5E%7B%5Ccirc%7D%20%5Cdfrac%7Bd%5Ctheta%7D%7Bdt%7D%3D-%5Cdfrac%7B21%7D%7B10%5E2%7D%5Ctimes%20%28-1%29)
![\dfrac{d\theta}{dt}=0.038\ rad/s](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5Ctheta%7D%7Bdt%7D%3D0.038%5C%20rad%2Fs)
Therefore rate of change in the angle is 0.038\ rad/s