Answer:
0.82 mm
Explanation:
The formula for calculation an  bright fringe from the central maxima is given as:
 bright fringe from the central maxima is given as:

so for the distance of the second-order fringe when wavelength  = 745-nm can be calculated as:
 = 745-nm can be calculated as:

where;
n = 2
  = 745-nm
 = 745-nm 
D = 1.0 m
d = 0.54 mm
 substituting the parameters in the above equation; we have:

 = 0.00276 m
 = 0.00276 m
 = 2.76 × 10 ⁻³ m
 = 2.76 × 10 ⁻³ m
The distance of the second order fringe when the wavelength  = 660-nm is as follows:
 = 660-nm is as follows:

 = 1.94 × 10 ⁻³ m
 = 1.94 × 10 ⁻³ m
So, the distance apart the two fringe can now be calculated as:

 = 2.76 × 10 ⁻³ m - 1.94 × 10 ⁻³ m
 = 2.76 × 10 ⁻³ m - 1.94 × 10 ⁻³ m
 = 10 ⁻³ (2.76 - 1.94)
 = 10 ⁻³ (2.76 - 1.94)
 = 10 ⁻³ (0.82)
 = 10 ⁻³ (0.82)
 = 0.82 × 10 ⁻³ m
 = 0.82 × 10 ⁻³ m
 =  0.82 × 10 ⁻³ m
 =  0.82 × 10 ⁻³ m 
 = 0.82 mm
 = 0.82 mm
Thus, the distance apart the second-order fringes for these two wavelengths  = 0.82 mm
 
        
             
        
        
        
Answer:
the angular velocity of the car is 12.568 rad/s.
Explanation:
Given;
radius of the circular track, r = 0.3 m
number of revolutions  per second made by the car, ω = 2 rev/s
The angular velocity of the car in radian per second is calculated as;
From the given data, we convert the angular velocity in revolution per second to radian per second.

Therefore, the angular velocity of the car is 12.568 rad/s.
 
        
             
        
        
        
A pure substance that cannot be decomposed by ordinary chemical change. . Energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means.