Answer: star
Exoplanets are the planets present in the other star system. There are billions of stars in our galaxy and we expect presence of other planetary systems similar to our solar system. Exoplanets can be detected by a) radial velocity method b) astrometric method c) transient method. In the radial method, we observe the changes in the spectrum of the light coming from star when an exoplanet is orbiting it. There is change in gravitational pull as the planets goes around the star. It sometimes pulls into smaller orbit. like this the star wobbles back and forth. By measuring the blueshift and redshift in the star's spectrum, exoplanet can be discovered.
Answer:
270
Explanation:
Once you add more mass to something the mass doesn’t go away you add more mass.
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Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.
The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.
When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.
Learn more: brainly.com/question/2510654
According to Einstein the energy of photon is given by the equation,
E = hν = h . c/λ
where h is Planck's constant, c is the speed of light, ν is the frequency of light and λ is the wavelength of light.
Given, wavelength of photon = 413 nm = 413 x 10⁻⁹ m
Conversion factor: 1 nm = 10⁻⁹ m
c = 3 x 10⁸ m/s
h = 6.626× 10⁻³⁴ J.s
Substituting the data into the equation we get,
E = h . c/λ
E = 6.626× 10⁻³⁴ J.s x (3 x 10⁸ m/s) / 413 x 10⁻⁹ m
E = 4.8 x 10⁻¹⁹ J
The energy of this blue light is 4.8 x 10⁻¹⁹ J
22 Newton’s to the right but I’m not to sure make sure to check other answers!
