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3 years ago

Which of the following popular sayings is an example of a true scientific theory?

Chemistry

2 answers:

algol133 years ago

8 0

Answer:

1st or 2nd options

Explanation:

Yes, carrots will help improve eyesight. The body uses beta-carotene to make vitamin A, and “vitamin A is really important, there's no question about that,” says Emily Chew, deputy clinical director at the National Eye Institute.

Warm milk because milk has small amounts of tryptophan, the raw material the brain uses to build both serotonin and melatonin. These are compounds that help us relax and prepare for sleep.

Hope this helps :D

Iteru [2.4K]3 years ago

4 0

I think the correct answer is the first option. Among the popular sayings given, the true scientific theory is the statement "Eating lots of carrots will improve your eyesight." This is because many studies and researches had been done and proved that carrots really helps improve or maintain the health of the eyes.

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If the pressure of a gas is 2.43 atm what is it’s pressure in kpa

Viktor [21]

The pressure of the gas is 246 kPa.

p = 2.43 atm × (101.325 kPa/1 atm) = 246 kPa

8 0

3 years ago

A 500.0-mL buffer solution is 0.100 M in HNO2 and 0.150 M in KNO2. Determine if each addition would exceed the capacity of the b

likoan [24]

Answer:

no one additions exceed the capacity of the buffer

Explanation:

given

Volume buffer = 500.0 mL = 0.5 L

mol HNO₂ = 0.5 L × 0.100 mol/L = 0.05 mol HNO₂

mol NO₂⁻ = 0.5 L × 0.150 mol/L = 0.075 mol NO₂⁻

solution

we know when any base more than 0.05 (HNO2) than exceed buffer capacity

and when any base more than 0.075 (KNO2) than exceed buffer capacity

when we add 250 mg NaOH (0.250 g)

than molar mass NaOH =40 g/mol

and mol NaOH = 0.250 g ÷ 40g/mol

mol NaOH = 0.00625 mol

0.00625 mol NaOH will be neutralized by 0.00625 mol HNO₂

so it would not exceed the capacity of the buffer.

and

when we add 350 mg KOH (0.350 g)

than molar mass KOH =56.10 g

and mol KOH = 0.350 g ÷ 56.10 g/mol

mol KOH = 0.0062 mol

here also capacity of the buffer will not be exceeded

and

now we add 1.25 g HBr

than molar mass HBr = 80.91 g/mol

and mol HBr = 1.25 g ÷ 80.91 g/mol

mol HBr = 0.015 mol

0.015 mol Hbr will neutralize 0.015 mol NO₂⁻

so the capacity will not be exceeded.

and

we add 1.35 g HI

molar mass HI = 127.91 g/mol

so mol HI = 1.35 g ÷ 127.91 g/mol

mol HI = 0.011 mol

capacity of the buffer will not be exceed

3 0

3 years ago

About how long is 1 meter?

lyudmila [28]

It should be 3 feet... I did something like this one day in school but I’m trying to remember

3 0

4 years ago

Read 2 more answers

Labels of many food products have expiration dates, at which point they are typically removed from the supermarket shelves. A pa

White raven [17]

Answer:

Explanation:

Since it first order, we use order rate equation

In ( $\frac{A1}{A0}$ ) = -kt where A1 is the final quality = 0.8 (80%), A0 is the initial quality = 1 ( 100%)

also, t half life = $\frac{In2}{k}$ where k is rate constant

k = $\frac{In 2}{45 days}$ = 0.0154

In ( $\frac{0.8}{1}$ ) = - 0.0154 t

-0.223 / -0.0154 = t

t = 14.49 approx 14.5 days from the date the yogurt was packaged

6 0

4 years ago

How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)

11Alexandr11 [23.1K]

$98.56 dm^3$ of oxygen at STP would be required to react completely with 38.8g of propane.

Given that :

molar mass of propane = 44 g/mol

mass of propane = 38.8 g

∴ Moles present in 38.8 g of propane = $\frac{38.8}{44}$ = 0.88 mole

applying rule of balanced equations

1 mole of propane = 5 moles of oxygen

0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen

Note : volume of 1 mole of oxygen at STP = $22.4 dm^3$

∴Total volume of oxygen required at STP = 22.4 * 4.4 = $98.56 dm^3$

Hence we can conclude that the volume of oxygen at STP required to react completely $98.56 dm^3$

Learn more : brainly.com/question/16998374

5 0

2 years ago