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DanielleElmas [232]
3 years ago
10

A reaction between ammonia gas and chlorine gas produces

Chemistry
2 answers:
7nadin3 [17]3 years ago
7 0

Answer:

32.25

Explanation:

8NH3 + 3Cl2 → 6NH4Cl + N2

NH3 = 17 g/mol

number of moles = 1

NH4Cl= 43 g/mol

number of moles = 3/4

mass= 43 × ¾ ≈ 32.25 g

hodyreva [135]3 years ago
4 0

Answer:

40.1

Explanation:

its correct your welcome

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Which statement is correct
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Indicate which reaction will occur faster. explain your reasoning. select the single best answer. solvolysis of 1−chloro−2,2−dim
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The tert-butyl chloride in ethanol would surely react faster than the solvolysis of 1-chloro-2,2-dimethyl propane. It is known that both reactions are under the SN2 category so it would be hard for these reactions to occur. However, SN1 reactions are possible because of the ethanol which is a polar solvent. Both would form carbocations but tert-butyl chloride forms a more stable carbocation while the 1-chloro-2,2-dimethyl propane forms a primary carbocation only. 
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3 years ago
A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t  1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= \frac{w}{W} = \frac{w}{V}= density

P = \frac{density RT}{M}       density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = \frac{0.525 x 0.0821 x 608.15 }{M}

  M    = 34.61

         

to calculate the Kc

Kc=\frac{ [NO] [O2]}{NO2}

  \frac{1-2x}{1+x} x M NO2 + \frac{2x}{1+x} M NO+ \frac{x}{1+x} M O2

Putting the values as molecular weight of NO2, NO,O2

\frac{46(1-2x) +30(2x)+32x}{1+x}

34.61= \frac{46}{1+x}

x= 0.33

Kc= \frac{4x^2)x}{1-2x^2}

    putting the values in the above equation

Kc = 0.00662

     

5 0
2 years ago
A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centr
IRISSAK [1]
<h3><u>Answer;</u></h3>

<em><u> = 48,828.125 mi/hr²</u></em>

<h3><u>Explanation and solution</u>;</h3>
  • <em><u>Centripetal acceleration is the rate of change of angular velocity. Centripetal acceleration occurs towards the center of the circular path along the radius of the circular path</u></em>.
  • Centripetal acceleration is given by; <em>V²/r ; </em>

<em>V = 125 mi/h and r = 0.320 miles </em>

  • <em>Thus; centripetal acceleration = 125²/0.320 </em>

                                                  =15625/0.320

                                                 <em><u> = 48,828.125 mi/hr²</u></em>

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3 years ago
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