All categories

3 years ago

A reaction between ammonia gas and chlorine gas produces

Chemistry

2 answers:

7nadin3 [17]3 years ago

7 0

Answer:

32.25

Explanation:

8NH3 + 3Cl2 → 6NH4Cl + N2

NH3 = 17 g/mol

number of moles = 1

NH4Cl= 43 g/mol

number of moles = 3/4

mass= 43 × ¾ ≈ 32.25 g

hodyreva [135]3 years ago

4 0

Answer:

40.1

Explanation:

its correct your welcome

You might be interested in

What volume (in liters) of a solution contains 0.14 mol of KCl?

oksano4ka [1.4K]

Answer:

$\boxed {\boxed {\sf 0.078 \ L }}$

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

$molarity= \frac{moles \ of \ solute}{liters \ of \ solution}$

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

moles of solute = 0.14 mol KCl
molarity= 1.8 mol KCl/ L
liters of solution=x

Substitute these values/variables into the formula.

$1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}$

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

$\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}$

$1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl$

$1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl$

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

$\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}$

$x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}$

The units of moles of potassium chloride cancel.

$x= \frac{0.14 }{1.8 L}$

$x=0.07777777778 \ L$

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

$x \approx 0.078 \ L$

There are approximately <u>0.078 liters of solution.</u>

5 0

3 years ago

How many liters of air must react with 2500 mL of hexane in order for combustion to occur completely. The percentage of oxygen i

bagirrra123 [75]

Answer:

118750 ml

Explanation:

The chemical equation for complete combustion of hexane is given as;

2C6H14 + 19O2 → 12CO2 + 14H2O

From the equation of the reaction;

2 mol of C6H14 reacts with 19 mol of O2

2 ml of C6H14 reacts with 19 ml of O2

2500 mL of C6H14 would react with x ml of O2

2 = 19

2500 = x

x = 2500 * 19 / 2 = 23750 ml

Since oxygen is 20% of air;

23750 = 20 / 100 * (Volume of air)

Volume of air = 23750 * 100 / 20 = 118750 ml

7 0

3 years ago

Animals get energy from the food that they eat. However, when the molecules from the food enter your cells, how do the molecules

sattari [20]

Answer:

The ATP is broken down into glucose which the cells use for energy.

6 0

3 years ago

Write a net ionic equation to show how codeine, c18h21o3n, behaves as a base in water.

Lera25 [3.4K]

Actually, the ionic equation for this is a reversible equation since codeine is a weak base. Any weak base or weak acids do not completely dissociate which makes them a reversible process. The ionic equation for this case is:

<span>C18H21O3N + H3O+ </span><=> C18H21O3NH+ + H2O

7 0

4 years ago

An object was measured by a worker as

Alexeev081 [22]

Answer:.633

Explanation:

I have know idea but it was right

3 0

3 years ago