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Sunny_sXe [5.5K]
3 years ago
8

A person whose mass is m = 70.0 kg m=70.0 kg steps on a mechanical bathroom scale placed on an inclined plane that makes the ang

le α = 22.3 ∘ α=22.3∘ with the horizontal. What is the reading on the scale?
Physics
1 answer:
oee [108]3 years ago
8 0

Answer:The reading on the scale is 64.76kg

Explanation:

According to Newton's 3rd law,when a person exerts a force on a plane,the plane simultaneously exerts a force equal in magnitude and opposite.

Given: mass=70kg ,alpha= 22.3°

Mg=mg×cos alpha= 70kg× cos22.3°=

70× 0.9252= 64.76kg

The reading on the scale is 64.76kg

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Answer:

c=71.4m/s

\theta=8.54\textdegree

Explanation:

From the question we are told that

Initial velocity of 60 m/s

Wind speed V_w= 15 m/s \angle  45 \textdegree

Generally Resolving vector mathematically

  sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6

Generally the equation Pythagoras theorem is given mathematically by

c^2=a^2+b^2

c^2=10.6^2 +(10.6+60)^2

c=\sqrt{10.6^2 +(10.6+60)^2}

Therefore Resultant velocity (m/s)

c=71.4m/s

b)Resultant direction

Generally the equation for solving Resultant direction

\theta=tan^-1(\frac{y}{x})

Therefore

\theta=tan^-1(\frac{10.6}{70.6})

\theta=8.54\textdegree

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2 years ago
What is the kinetic energy of a 0.5 kg puppy that is running 1.5m/s
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3 years ago
A piece of transparent material that is used to focus light and form a image
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Convex Lenses are used to focus light and form a image. They are transparent.

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Car a runs a red light and broadsides car b, which is stopped and waiting to make a left turn. car a has a mass of 1,800kg. car
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The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:

mA vA + mB vB = m v

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since m is the total mass, m = mA + mB, we can write the equation as:

mA vA + mB vB = (mA + mB) v

furthermore, car B was at a stop signal therefore vB = 0, hence

mA vA + 0 = (mA + mB) v

1800 (vA) = (1800 + 1500) (7.1 m/s)

<span>vA = 13.02 m/s</span>

7 0
3 years ago
A spring with a spring constant of 350 N/m pulls a door closed. How much work is done as the spring pulls the door at a constant
german

The work done to stretch the spring will be 112 J.

<h3>What is spring force?</h3>

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

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The given data in the problem is;

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The work is done to stretch the spring is;

\rm W= \frac{1}{2} kx^2 \\\\ W=\frac{1}{2} \times 350 \times (0.850-0.050)^2 \\\\ W=0.5 \times 350 \times (0.80)^2 \\\\W=112 \ J

To learn more about the spring force refer to the link;

brainly.com/question/4291098

#SPJ1

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