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3 years ago

Help!! i need to know which letter has the highest speed, the middlest speed and the lowest speed!!

Physics

1 answer:

saveliy_v [14]3 years ago

5 0

Answer:

From highest speed to lowest speed:

A, C, B

Explanation:

On a position time graph, the slope of a line would represent the velocity, since the rate of change represents how many meters traveled in the given time.

The larger the slope, the faster the velocity; the steeper the line, the faster the speed.

Since line B is negative, you know that velocity is negative so it automatically has the lowest speed.

Out of lines A and C, since A is steeper, you know that A has a faster speed.

In conclusion:

A is the fastest

C is the middle

B is the slowest

You might be interested in

A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What

spin [16.1K]

Answer:

The wavelength is $\lambda_ 1 = 574.2 nm$

Explanation:

From the question we are told that

The thickness is $t = 198 nm = 198 *10^{-9 }\ m$

The refractive index of the non-reflective coating is $n_m = 1.45$

The refractive index of glass is $n_g = 1.50$

Generally the condition for destructive interference is mathematically represented as

$2 * n_m * t * cos (\theta) = n * \lambda$

Where $\thata$ $\theta$ is the angle of refraction which is 0° when the light is strongly transmitted

and n is the order maximum interference

$\lambda = \frac{2 * n * t * cos (\theta )}{n}$

at the point n = 1

$\lambda _1 = \frac{2 * 1.45 * 198*10^{-9} * cos (0 )}{1}$

$\lambda_1 = 574.2 *10^{-9}$

$\lambda_1 = 574.2 nm$

at n =2

$\lambda _2 = \frac{\lambda _1 }{2}$

$\lambda _2 = \frac{574.2*10^{-9} }{2}$

$\lambda _2 = 2.87 1 *10^{-9} \ m$

$\lambda _2 = 287. 1 nm$

Now we know that the wavelength range of visible light is between

$390 \ nm \to 700 \ nm$

So the wavelength of visible light that is been transmitted is

$\lambda_ 1 = 574.2 nm$

6 0

4 years ago

A wire delivers 120 C of charge in 40 s.

Neporo4naja [7]

Answer:

3 A

Explanation:

Charge is a product of current and time, expressed as Q=It where Q is charge in Coulombs, I is current in Amperes and t is time taken in seconds. Making I the subject of the formula then $I=\frac {Q}{t}$