Answer:
A) magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units
B)22.5° (clockwise form -ve X axis)
Explanation:
given vector = V1 = x i - 60 j
magnitude of V1 = 90
x - component can be found out by resultant formula
90^2 = x^2 + (-60)^2
x = 67.08 = 67.1 units (3sf)
FOR THE VECTOR 80 UNITS IN -VE X DIRECTION
The X component is -80-------(1)
The Y component is 0 ---------(2)
<u>For the x- component of new added vector:</u>
(1)----------- x + 67.1 = -80
x = -147.1 = -147.1
<u>For the y- component of new added vector:</u>
<u>(</u>2)---------- y - 61 = 0
y = 61.0 (3sf)
the new added vector is = -147.1 i + 61 j
magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units
direction = arctan (61 / 147.1)
= 22.5° (clockwise form -ve X axis)
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