Answer:
![\frac{Ie}{lm} = 1.10*10^{-3}](https://tex.z-dn.net/?f=%5Cfrac%7BIe%7D%7Blm%7D%20%3D%201.10%2A10%5E%7B-3%7D)
Explanation:
GIVEN DATA:
Engine operating speed nf = 8325 rev/min
engine angular speed ni= 12125 rev/min
motorcycle angular speed N_m= - 4.2 rev/min
ratio of moment of inertia of engine to motorcycle is given as
![\frac{Ie}{lm} = \frac{-N}{(nf-ni)}](https://tex.z-dn.net/?f=%5Cfrac%7BIe%7D%7Blm%7D%20%3D%20%5Cfrac%7B-N%7D%7B%28nf-ni%29%7D)
![\frac{Ie}{lm} = \frac{-(-4.2)}{(12125 - (8325))}](https://tex.z-dn.net/?f=%5Cfrac%7BIe%7D%7Blm%7D%20%3D%20%5Cfrac%7B-%28-4.2%29%7D%7B%2812125%20-%20%288325%29%29%7D)
![\frac{Ie}{lm} = 1.10*10^{-3}](https://tex.z-dn.net/?f=%5Cfrac%7BIe%7D%7Blm%7D%20%3D%201.10%2A10%5E%7B-3%7D)
Answer:
Explanation:
the net force on the right left is 25 N and is directed upward
the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero
i hope this will help you
Answer:
so, why we have to find here..
<h3>stay safe healthy and happy.</h3>
Answer:
The maximum height reached by the water is 117.55 m.
Explanation:
Given;
initial velocity of the water, u = 48 m/s
at maximum height the final velocity will be zero, v = 0
the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².
The maximum height reached by the water is calculated as follows;
v² = u² + 2gh
where;
h is the maximum height reached by the water
0 = u² + 2gh
0 = (48)² + ( 2 x -9.8 x h)
0 = 2304 - 19.6h
19.6h = 2304
h = 2304 / 19.6
h = 117.55 m
Therefore, the maximum height reached by the water is 117.55 m.