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scZoUnD [109]
3 years ago
10

determine if the quadratic equation has 2 solutions, one, or 2 imaginary solutions by using the descriminant

Mathematics
1 answer:
Maurinko [17]3 years ago
7 0

Hello from MrBillDoesMath!

Answer:

31a.  2 real roots

31b   2 complex roots

Discussion:

31a.

2x^2 + 3x - 6 = 0

Using standard quadratic notation, the above equation has a  = 2, b = 3 and c = -6. The discriminant is given by b^2 - 4ac, which is

3^2 - 4*2*(-6) = 9 + 48 = 57 > 0, so the quadratic has 2 real roots


31b.

The equation is equivalent to  16x^2 + 10x  +3 = 0. Its discriminant is

10^2 - 4 * (16) * (3) = 100 - 192 = -92 so this equation has two complex roots



Regards,  

MrB


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3 years ago
Please help
user100 [1]

Answer:

Length of garden will be 30 metres.

Step-by-step explanation:

Let the Width of garden be x metres.

then,

Length of garden will be (x+6) metres.

Area = Length × Breadth

720 = x X (c+6)

720 = x²+6x

0 = x²+6x-720

As we can see above equation is a quadratic equation in the form of ax²+bx+C.

so,

=  \frac{ - b ±  \sqrt{{b}^{2} - 4ac}  }{2a}  \\ =   \frac{ - 6 ±   \sqrt{{6}^{2} - 4 \times 1 \times  - 720}  }{2}  \\ =    \frac{ - 6 ±  \sqrt{36 + 2880} }{2}  \\  =   \frac{ - 6 ±  \sqrt{2916} }{2}  \\  =   \frac{ - 6 ± 54}{2}\\= \frac{-6+54}{2} ... \frac{ - 6 - 54}{2}  \\  =  \frac{48}{2} ... \frac{ - 60}{2}  \\  = 24... - 30

One of the Roots of the Quadratic equation is 24 and other is -30.

And as we know width of any garden cannot be negative so the width of garden will be 24 metres.

As we got the width,

adding 6 to it will give us the Length,

So,

24 metres + 6 = 30 metres.

Length of the garden is 30 metres.

Hope It Helped You ;)

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@khuturr_

8 0
3 years ago
How do i total this please help<br> 8.3m<br> 5.2m<br> 4.36m<br> 42.1m<br> 86.1m
I am Lyosha [343]
Add them all up so it would equal 146.06
3 0
3 years ago
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