Question

Please solve the following right triangle below. The round the following decimal answers to the nearest tenth.

Answer 1

$K=180^{\circ}-90^{\circ}-40^{\circ}=50^{\circ}$.

$KL=\sin(40^{\circ})\cdot8\approx5.1$.

$ML=\cos(40^{\circ})\cdot8\approx6.1$.

Hope this helps.