10
20
30 there u go
that the rounding
If n is 2, you substitute 2 for n and multiply 5(2)+8= 10 +8 = 18
Step-by-step explanation:
1. SAS
2. HL
3. AAS
4 AAS
I think I may be wrong check
5(x^2n-1)×(2x^3n-1) ^2
=20n3 x8 -20n2 x5 +20n x3 +20n x3 +5n x2-5
