218.4 grams of CaO is produced using 3.9 moles CaCO₃.
<h3>How we calculate weight of any substance from moles?</h3>
Moles of any substance will be defined as:
n = W / M
Given chemical reaction is:
CaCO₃ → CaO + CO₂
From the above equation it is clear that according to the concept of stoichiometry 1 mole of CaCO₃ is producing 1 mole of CaO. By using above formula, we calculate grams as follow:
W = n × M, where
n = no. of moles of CaO = 3.9 moles
M = molar mass of CaO = 56 g/mole
W = 3.9 × 56 = 218.4 g
Hence, 218.4 grams of Cao is produced.
<h3>How much grams do Cao's molecular weight equal?</h3>
Molecular weight of CaO. CaO has a molar mass of 56.0774 g/mol. Calcium Oxide is another name for this substance. Convert moles of CaO to grams or grams of CaO to moles. Calculation of the molecular weight: 40.078 + 15.9994 ›› Composition by percentage and element
<h3>How much calcium is required to create one mole of oxygen?</h3>
In order to create one mole of calcium oxide, the reaction between one mole of calcium (40.1 g) and half a mole of oxygen (16 g) is stoichiometric (56.1 g). This means that only 4.01 grams of calcium metal and 1.6 grams of oxygen can combine to generate 5.61 grams of calcium oxide.
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Answer: Climate change increases carbon in our atmosphere affecting the water. 97% of earth is ocean so the cO goes into the water creating the acidification. killing coral and plankton
Answer:
https://www.khanacademy.org/science/chemistry/oxidation-reduction/batter-galvanic-voltaic-cell/v/redox-reaction-from-dissolving-zinc-in-copper-sulfate
Explanation:
watch the vid
1&3 are the answers lmk if it’s wrong
Answer:
8.45 moles are produced
Explanation:
CaCl₂ + Na₂CO₃ → CaCO₃ + 2 NaCl
From the equation, we can see that for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl
to calculate how many moles of CaCO₃ ,we simply multiply multiply each by the 8.45 moles of CaCl₂ which will reacts
these is because for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl
therefore we have every 1x8.45(8.45) mole of CaCl₂ and 1x8.45(8.45) mole Na₂CO₃ will give 1x8.45(8.45) mole of CaCO₃ and 2x8.45(16.9) moles of NaCl
8.45 moles are produced in the reaction