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son4ous [18]
3 years ago
9

Is layers of sediment forming at the bottom of the ocean erosion?

Chemistry
1 answer:
kiruha [24]3 years ago
5 0
Yes layers of sediment form at the bottom of the ocean.
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What is the relationship between the internal energy of a substance and its particle movement?
ss7ja [257]

Answer: The closeness, arrangement and motion of the particles in a substance change when it changes state. Materials are a store of internal energy , due to the motion of particles and the chemical bonds between them. When a substance is heated, its internal energy increases: the movement of its particles increases.

Explanation:

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Please help me out !!
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27Hq)+3816(7/ 23q09)
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4NH3 + 5O2-&gt; 4NO + 6H2O<br><br> How many molesof NO are formed if 824g of NH3 react ?
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824 g NH3 (1 mol/17 g NH3) (4 mol NO/4mol NH3)

48.47 moles NO
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3 years ago
Which of the following statements best describes what happens to water during vaporization?
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Read 2 more answers
What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The densit
jok3333 [9.3K]

Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution  = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

7 0
2 years ago
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