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son4ous [18]
3 years ago
9

Is layers of sediment forming at the bottom of the ocean erosion?

Chemistry
1 answer:
kiruha [24]3 years ago
5 0
Yes layers of sediment form at the bottom of the ocean.
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Ight this is for all em boy and girls out there who wanna be in an actual loving relationship. Not for the ones who just wanna g
jekas [21]

Answer:

yooooo

Explanation:

4 0
3 years ago
Which type of rock forms as a result of cooling and crystallization?
Dovator [93]

Answer:

Igneous rock is the type of rock that forms as a result of cooling an crystallization

Explanation:

  • Rocks are either sedimentary, igneous or metamorphic based on the chemical composition and the mode of formation.
  • Igneous rocks are formed as a result of the cooling and crystallization of magma from volcanic eruptions.
  • Igneous rocks are either intrusive, which form deep in the crust or extrusive which form on the surface of the earth.
  • Sedimentary rocks are formed as a result of deposition, and cementation of sediments.
  • Metamorphic rocks, on the other hand, are formed from the sedimentary and igneous rocks during the rock cycle.

7 0
3 years ago
A reaction requires 2.5 moles of zinc oxide. how many grams would this equate to?​
Nady [450]

Answer: 45.038

Explanation: 2.016 H (2*1.008) + 15.999 O (1*15.999)

4 0
2 years ago
What is the excess reactant in the combustion of 23 g of methane in the open atmosphere?
Marta_Voda [28]

Answer : The excess reactant in the combustion of methane in opem atmosphere is O_{2} molecule.

Solution : Given,

Mass of methane = 23 g

Molar mass of methane = 16.04 g/mole

The Net balanced chemical reaction for combustion of methane is,

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

First we have to calculate the moles of methane.

\text{ Moles of methane}=\frac{\text{ Given mass of methane}}{\text{ Molar mass of methane}} = \frac{23g}{16.04g/mole} = 1.434 moles

From the above chemical reaction, we conclude that

1 mole of methane react with the 2 moles of oxygen

and 1.434 moles of methane react to give \frac{2moles\times 1.434moles}{1moles} moles of oxygen

The Moles of oxygen = 2.868 moles

Now we conclude that the moles of oxygen are more than the moles of methane.

Therefore, the excess reactant in the combustion of methane in open atmosphere is O_{2} molecule.


6 0
3 years ago
Which method is best for separating most of a solid from a gas quickly?
klemol [59]

Answer:

I think the answer is distillation

8 0
3 years ago
Read 2 more answers
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