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FromTheMoon [43]
3 years ago
10

22.5 mL of an HNO3 solution were titrated with 31.27 mL of a .167 M NaOH solution to reach the equivalence point. What is the mo

larity of the HNO3 solution
Chemistry
1 answer:
natulia [17]3 years ago
3 0

Answer:

M₂ = 0.23 M

Explanation:

Given data:

Volume of HNO₃ = 22.5 mL

Volume of NaOH = 31.27 mL

Molarity of NaOH = 0.167 M

Molarity of HNO₃ = ?

Solution:

M₁ = Molarity of NaOH

V₁ = Volume of NaOH

M₂ = Molarity of HNO₃

V₂ = Volume of HNO₃

M₁V₁ = M₂V₂

0.167 M × 31.27 mL = M₂ × 22.5 mL

5.2 M. mL = M₂ × 22.5 mL

M₂ =  5.2 M. mL /22.5 mL

M₂ = 0.23 M

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3 years ago
Ns
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Answer:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + H₂O

Explanation:

Chemical equation:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + H₂O

Balanced chemical equation:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + 2H₂O

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6 0
3 years ago
What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
damaskus [11]

Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

7 0
3 years ago
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Answer:

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3 years ago
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