Answer:
The energy absorbed by the atomic electrons in the mercury atom is J
Explanation:
Given:
Potential V
According to the conservation law,
Loss in kinetic energy = Gain in potential energy
Here, energy absorbed by the atomic electrons is given by,
Where ( charge of electron )
J
Therefore, the energy absorbed by the atomic electrons in the mercury atom is J
Answer:
The solution(s) are in order with respect to the attachments
Joules ; 5. Adding the same amount of heat to two different objects will produce the same increase in temperature ; 2. Same speed in both ; 2. A
Explanation:
Diagram 1 ( Liquid Nitrogen ) : So as you can see, we want our units in Joules here, and can therefore multiply the mass of gaseous nitrogen and the latent heat of liquid nitrogen, to cancel the units kg, and receive our solution - in terms of Joules. Let's do it.
q ( energy removed ) = mass of nitrogen latent heat of liquid nitrogen,
q = 1.3 kg 2.01
10⁵ J / kg =
=
=
=
Joules =
kiloJoules = 2.613
10⁵Joules is the energy that must be removed
Diagram 2 : The same amount of heat does not necessarily mean the same increase in temperature for two different objects. The increase in temperature depends on the specific heat capacity of the substance. Therefore your solution is 5 ) Adding the same amount of heat to two different objects will produce the same increase in temperature.
Diagram 3 : The temperatures in both glasses are the same, and hence the molecules have the same average speed. Therefore your solution is 2 ) Same speed in both.
Diagram 4 : Glass A has more water molecules, and hence has more thermal energy. Your solution is 2 ) A.
Answer:
0.686 g of ice melts each second.
Solution:
As per the question:
Cross-sectional Area of the Copper Rod, A =
Length of the rod, L = 19.6 cm = 0.196 m
Thermal conductivity of Copper, K =
Conduction of heat from the rod per second is given by:
where
= temperature difference between the two ends of the rod.
Thus
Now,
To calculate the mass, M of the ice melted per sec:
where
= Latent heat of fusion of water = 333 kJ/kg