<h3><u>Answer;</u></h3>
C) atoms are more stable when they combine with other atoms
<h3><u>Explanation</u>;</h3>
- Atoms are the smallest particles of an element that can take part in a chemical reaction.
- <em><u>Atoms seldom exist as independent particles in nature. Nearly all substances are made up of combinations of atoms that are held together by chemical bonds, which are forces of attractions between the nuclei and valence electrons of different atoms that join the atoms together.</u></em>
Answer:243joules
Explanation:
Mass(m)=54kg
Velocity(v)=3m/s
Kinetic energy =(m x v^2)/2
Kinetic energy =(54 x 3^2)/2
Kinetic energy =(54 x 9)/2
Kinetic energy =486/2
Kinetic energy =243joules
Answer:
20m/s^2
Explanation:
Acceleration=Change in velocity/time taken for change
40-20/1
20m/s^2
Answer:
The magnitude of force must you apply to hold the platform in this position = 888.89 N
Explanation:
Given that :
Workdone (W) = 80.0 J
length x = 0.180 m
The equation for this work done by the spring is expressed as:
![W = \frac{1}{2}k_{eq}x^2](https://tex.z-dn.net/?f=W%20%3D%20%5Cfrac%7B1%7D%7B2%7Dk_%7Beq%7Dx%5E2)
Making the spring constant
the subject of the formula; we have:
![k_{eq} = \frac{2W}{x^2}](https://tex.z-dn.net/?f=k_%7Beq%7D%20%3D%20%5Cfrac%7B2W%7D%7Bx%5E2%7D)
Substituting our given values, we have:
![k_{eq} = \frac{2*80}{0.180^2}](https://tex.z-dn.net/?f=k_%7Beq%7D%20%3D%20%5Cfrac%7B2%2A80%7D%7B0.180%5E2%7D)
![k_{eq} = 4938.27 \ N.m^{-1}](https://tex.z-dn.net/?f=k_%7Beq%7D%20%3D%204938.27%20%5C%20N.m%5E%7B-1%7D)
The magnitude of the force that must be apply to the hold platform in this position is given by the formula :
![F = k_{eq}x](https://tex.z-dn.net/?f=F%20%3D%20k_%7Beq%7Dx)
![F = 4938.27*0.180](https://tex.z-dn.net/?f=F%20%3D%204938.27%2A0.180)
F = 888.89 N
The pressure exerted by a fluid solely relies on the depth or height of the fluid, its density, and the gravitational constant. These three are related in the equation:
Pressure = density x g x height
In the problem, point A is within the block inside the tank. The water above the block is assumed to be 0.6 meters. This gives a point A pressure of:
P = 1000 kg/m^3 * 9.81 m/s^2 * 0.6 m = 5,886 Pa or 5.88KPa