Question

When the tube is filled with mercury vapor, as in this case, a sharp drop in the collected current is observed when the accelerating potential reaches 4.9 v. the current drops suddenly to a negligible value and slowly increases again when the accelerating potential is above 4.9 v. what is the energy e absorbed by the atomic electrons in the mercury atom when the accelerating potential is 4.9 v?

Answer 1

Answer:

The energy absorbed by the atomic electrons in the mercury atom is $7.84 \times 10^{-19}$ J

Explanation:

Given:

Potential $V = 4.9$ V

According to the conservation law,

   Loss in kinetic energy = Gain in potential energy

Here, energy absorbed by the atomic electrons is given by,

    $E = eV$

Where $e = 1.6 \times 10^{-19} C$       ( charge of electron )

    $E = 1.6 \times 10^{-19 } \times 4.9$

    $E = 7.84 \times 10^{-19}$ J

Therefore, the energy absorbed by the atomic electrons in the mercury atom is $7.84 \times 10^{-19}$ J