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Colt1911 [192]
3 years ago
10

44. Belly-flop Bernie dives from atop a tall flagpole into a swimming pool below. His potential energy at the top is 10,000 J (r

elative to the surface of the pool). What is his kinetic energy when his potential energy is reduced to 1000 J
Physics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

9000 J

Explanation:

Potential energy at the top = 10,000 J

Final potential energy = 1000 J

use the conservation of mechanical energy

Potential energy at top + kinetic energy at top = potential energy at a point + kinetic energy at that point.

10000 + 0 = 1000 + kinetic energy

kinetic energy = 10000 - 1000

kinetic energy = 9000 J

Thus, the kinetic energy is 9000 J.

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Globalization is the process of
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Answer: Globalization is the process of interaction and integration among people, companies, and governments worldwide.

Explanation:

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3 years ago
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Block A has a mass of 0.5kg, and block B has a mass of 2kg. Block is is released at a height of 0.75 meters above B. The coeffic
VikaD [51]

Answer:

0.075 m

Explanation:

The picture of the problem is missing: find it in attachment.

At first, block A is released at a distance of

h = 0.75 m

above block B. According to the law of conservation of energy, its initial potential energy is converted into kinetic energy, so we can write:

m_Agh=\frac{1}{2}m_Av_A^2

where

g=9.8 m/s^2 is the acceleration due to gravity

m_A=0.5 kg is the mass of the block

v_A is the speed of the block A just before touching block B

Solving for the speed,

v_A=\sqrt{2gh}=\sqrt{2(9.8)(0.75)}=3.83 m/s

Then, block A collides with block B. The coefficient of restitution in the collision is given by:

e=\frac{v'_B-v'_A}{v_A-v_B}

where:

e = 0.7 is the coefficient of restitution in this case

v_B' is the final velocity of block B

v_A' is the final velocity of block A

v_A=3.83 m/s

v_B=0 is the initial velocity of block B

Solving,

v_B'-v_A'=e(v_A-v_B)=0.7(3.83)=2.68 m/s

Re-arranging it,

v_A'=v_B'-2.68 (1)

Also, the total momentum must be conserved, so we can write:

m_A v_A + m_B v_B = m_A v'_A + m_B v'_B

where

m_B=2 kg

And substituting (1) and all the other values,

m_A v_A = m_A (v_B'-2.68) + m_B v_B'\\v_B' = \frac{m_A v_A +2.68 m_A}{m_A + m_B}=1.30 m/s

This is the velocity of block B after the collision. Then, its kinetic energy is converted into elastic potential energy of the spring when it comes to rest, according to

\frac{1}{2}m_B v_B'^2 = \frac{1}{2}kx^2

where

k = 600 N/m is the spring constant

x is the compression of the spring

And solving for x,

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(2)(1.30)^2}{600}}=0.075 m

5 0
3 years ago
How much heat is needed to boil 120 kg of water ?
nekit [7.7K]
Q = mc<span>∆t, where:
q = energy flow
m = mass, 120 000 g
c = specific heat capacity, 4.81 J/gC
</span><span>∆t = change in temperature, ~75 (100 - 25, which is room temperature)

Substituting in the values, we get:
q = 120000 x 4.81 x 75 = 43290000 Joules = 43.29 MJ

Hope I helped!! xx


</span>
7 0
3 years ago
Identify the technologies that utilize electromagnetism. (Choose 2) Kitchen blender, silicon microchip, inclined plane, electric
Sav [38]

Answer: Kitchen blender and electric drill

Explanation:

8 0
3 years ago
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Find the x-component of this
Mashcka [7]

The horizontal or x component of the vector is 53.5 m.

<h3>What is the x component?</h3>

We know that a vector quantity must posses both magnitude and direction. In this case, of a vector is inclined at an angle then the vector could have a vertical and a horizontal component. Recall that vector may have have;

- A vertical component

- A horizontal component

Recall that when we resolve a vector, we are able to obtain the effective component of the vector in the given direction. It could be vertical or horizontal.

The horizontal component of the vector is V cos θ where V is the numerical value of the vector.

Thus the horizontal component is;

55.1 m Cos 13.9 = 53.5 m

Learn more about components of a vector:brainly.com/question/4179238

#SPJ1

8 0
1 year ago
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