Answer:
F = 19.1 N
Explanation:
To find the force exerted by the string on the block you use the following formula:
(1)
k: spring constant = 95.5 N/m
x: displacement of the block from its equilibrium position = 0.200 m
you replace the values of k and x in the equation (1):

Hence, the force exterted on the block is 19.1 N
Answer: 26 beats in 2 seconds
Explanation:
The number of beats per second = frequency of tuning fork 1 - frequency of tuning fork 2.
Given :
- frequency of tuning fork 1 = 500Hz
- frequency of tuning fork 2 = 487Hz
Thus,
Beats per second = 500 - 487
= 13 beats per second
Therefore in two(2) seconds, you will have 2 x 13 = 26 seconds.
When your'e in space you feel weightless blc there's no grsvity in space.
Answer:
New pressure (P2) = 22.92 Kpa (Approx)
Explanation:
Given:
Old pressure (P1) = 22 Kpa
Temperature (T1) = 287 K
Temperature (T2) = 299 K
Find:
New pressure (P2)
Computation:
P1 / T1 = P2 / T2
22 / 287 = P2 / 299
New pressure (P2) = 22.92 Kpa (Approx)