“a point at which rays of light, heat, or other radiation meet after being refracted or reflected.” Meaning multiple light rays or heat (and other forms of radiation) are all being refracted or reflecting to a certain point
They are helium nuclei, which consist of two protons and two neutrons. The net spin on an alpha particle is zero. They result from large, perilous atoms via a process called alpha decay.
<h3>What is
helium nuclei?</h3>
- The nucleus of the helium atom also understood as the α-particle, includes two protons and two neutrons, encompassed by two electrons.
- Alpha particles are helium nuclei with two protons and two neutrons attached. The development of their high mass and an electrical charge is their inability to infiltrate as deep as other particles such as protons and electrons.
- Particle beams contain α (alpha)-particles, β (beta)-particles, neutron beams, etc. α-particles are helium middles consisting of two protons and two neutrons that have lived removed at high speed, while β-particles are electrons removed from a nucleus. Particle shafts also include neutron beams and proton beams.
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Answer:
When focused light is projected onto the retina, it stimulates the rods and cones. The retina then sends nerve signals are sent through the back of the eye to the optic nerve. The optic nerve carries these signals to the brain, which interprets them as visual images.
Explanation:
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0.36 J of work is done in stretching the spring from 15 cm to 18 cm.
To find the correct answer, we need to know about the work done to strech a string.
<h3>What is the work required to strech a string?</h3>
- Mathematically, the work done to strech a string is given as 1/2 ×K×x².
- K is the spring constant.
<h3>What will be the spring constant, if 40N force is required to hold a 10 cm to 15 cm streched spring?</h3>
- The force experienced by a streched spring is given as Kx. x is the length of the spring streched from its natural length.
- Then K = Force / x.
- Here x = 15 - 10 = 5 cm = 0.05 m
- K = 40/0.05 = 800N/m.
<h3>What will be the work required to strech that spring from 15 cm to 18 cm?</h3>
- Work done = 1/2×k×x²
- Here x= 18-15=3cm or 0.03 m
- So, W= 1/2×800×0.03² = 0.36 J.
Thus, we can conclude that the work done is 0.36 J.
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True,
Explanation: because it’s the same reason that lighting touches the ground/ goes up to the sky, because it is trying to balance out its charges
