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wel
3 years ago
5

Consider electrons accelerated using a potential difference of (12.5 A B) kV before hitting a metal surface. Calculate the minim

um wavelength of the emitted x-rays. Give your answer in pm and with 3 significant figures.
Physics
1 answer:
Maslowich3 years ago
4 0

Answer:

Explanation:

Calculate The Minimum Wavelength Of The Emitted X-rays. Give Your Answer In Pm And With 3 Significant Figures. This problem has been solved! See the

Hope this helps! Have great day!

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A water wave travels 36 meters in 15 seconds. What is the speed of the wave?
atroni [7]
2.4 meters per second

I hope this helps
5 0
3 years ago
Read 2 more answers
It is a state of matter wherein particles are tightly packed, but are far enough apart to slide over one another.
NISA [10]

Particles that are closely packed but spaced apart enough to move over one another are called plasma. Option C is correct.

<h3>What is the plasma state of matter?</h3>

Plasma is a state of matter wherein particles are tightly packed but are far enough apart to slide over one another.

The following conditions are followed by the plasma state.

Hence, option C is correct.

To learn more about the plasma state refer;

brainly.com/question/5496865

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3 0
2 years ago
Pls hurry!! which organisms have no consumers to feed on them?
umka2103 [35]

Explanation:

All living organisms metabolize. That is the definition of life. So jr answer is no animal or organism that does not consume food.

6 0
3 years ago
When waves interfere together and result in a quieter sound is called
Alexus [3.1K]
That is called fully constructive interference.
8 0
3 years ago
A) the unstretched length of each elastic rope is 24m. The rope obeys hookes law. The vertical distance between P and Q is 35m.
solong [7]

Explanation:

a) The rope obeys Hooke's law, so:

F = k Δx

The elastic energy in the rope is:

EE = ½ k Δx²

Or, in terms of F:

EE = ½ F Δx

Use trigonometry to find the stretched length.

cos 20° = 35 / x

x =  37.25

So the displacement is:

Δx = 37.25 − 24

Δx = 13.25

The elastic energy per rope is:

EE = ½ (3.7×10⁴ N) (13.25 m)

EE = 245,000 J

There's two ropes, so the total energy is:

2EE = 490,000 J

Rounded to one significant figure, the elastic energy is 5×10⁵ J.

b) The elastic energy in the ropes is converted to gravitational energy.

EE = PE = mgh

5×10⁵ J = (1.2×10³ kg) (9.8 m/s²) h

h = 42 m

Rounded to one significant figure, the height is 40 m.  So the claim is not justified.

6 0
3 years ago
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