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ladessa [460]
3 years ago
11

You have an electric field with an intensity of 18 N/C at a

Physics
1 answer:
irinina [24]3 years ago
4 0

Answer:

108 v

Explanation:

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Suppose that instead of a long straight wire, a shortstraight wire was used. The distance from the wire to thepoint that the mag
vichka [17]

Answer:

Thus, if field were sampled at same distance, the field due to short wire is greater than field due to long wire.

Explanation:

The magnetic field, B of long straight wire can be obtained by applying ampere's law

B= \frac{\mu_0 I}{2\pi r}

I is here current, and r's the distance from the wire to the field of measurement.

The magnetic field is obviously directly proportional to the current wire. From this expression.

As the resistance of the long cable is proportional to the cable length, the short cable becomes less resilient than the long cable, so going through the short cable (where filled with the same material) is a bigger amount of currents. If the field is measured at the same time, the field is therefore larger than the long wire because of the short wire.

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3 years ago
9. What is the equivalent resistance of the circuit shown in the figure below?
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2 years ago
What 2 properties are used to classify radiation
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Large amount of energy is release

Temperature and pressure have no effect on the rate qt which radiation is emitted

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3 years ago
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eimsori [14]

Explanation:

d =  \frac{1}{2} a {t}^{2}  + vt \\ d = 75 \\ t = 5 \\ v = 0 \\  \\ 75 =  \frac{1}{2}  \times 25a + 0 \\ a = 6 \frac{m}{ {s}^{2} }  \\

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