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kompoz [17]
4 years ago
6

The shape of the earth is an _______ ________

Physics
1 answer:
Nastasia [14]4 years ago
3 0
The shape of the earth is an <span>oblate spheroid.</span>
You might be interested in
How do i find stretch? The problem in questioning has already given me the elastic energy and k-value, but I have no idea how to
finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

The expression to find the stretch (x) is x=\sqrt{\frac{2\times EPE}{k}}

Explanation:

Given:

Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.

To find: Elongation in the spring (x).

We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).

The formula to find EPE is given as:

EPE=\frac{1}{2}kx^2

Rewriting the above expression in terms of 'x', we get:

x=\sqrt{\frac{2\times EPE}{k}}

Example:

If EPE = 100 J and spring constant, k = 2 N/m.

Elongation or stretch is given as:

x=\sqrt{\frac{2\times EPE}{k}}\\\\x=\sqrt{\frac{2\times 100}{2}}\\\\x=\sqrt{100}=10\ m

Therefore, the stretch in the spring is 10 m.

So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.

6 0
3 years ago
Use this table of a school bus during morning pickups to answer the question.
AlexFokin [52]

Answer:

3.5

Explanation:

The answer should be 3.5

5 0
3 years ago
Read 2 more answers
Question 1 of 10
Debora [2.8K]

Answer:

V = λ f    (wavelength * frequency)

λ  = V / f = 343 m/s / 262 / s = 1.3 m

7 0
2 years ago
A friend waves &amp; yells at you. If the sound took 3.20 seconds to reach you and the speed of sound is 340 m/s,
xeze [42]

Answer:

1088 m

Explanation:

3.00 seconds times by 340 =1020+68=1088

5 0
3 years ago
An electron is placed 5.40 cm due north of a charged sphere and experienced a force of 8.30 x 10^-13 N due north. What is the el
ira [324]

Answer:

The electric field is E = 5.1*10^6N/C.

Explanation:

The force F on a charge q in an electric field E is given by

F = qE,

which can be rearranged to give

E = \dfrac{F}{q }

Now, the force on the electron is F = 8.30*10^{-13}N, and its charge is

q = 1.6*10^{-19}C; therefore,

E = \dfrac{8.30*10^{-13}N}{1.6*10^{-19}C}

\boxed{E = 5.1*10^6N/C}

4 0
3 years ago
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