Wich set of shapes contains members that are always similar to one another

Mathematics

2 answers:

Nadusha1986 [10]4 years ago

4 0

Hello.

The answer is

equilateral triangles
<span>All equilateral triangles are exactly the same as one another. They have the same size sides and the same shapes.
</span>
Have a nice day

iVinArrow [24]4 years ago

4 0

Answer: C) Equilateral Triangles

Any two triangles are similar if they have the same corresponding angles. In the case of two equilateral triangles, they both have 3 sets of 60 degree angles. So the angles pair up and we can prove them to be similar using the Angle Angle (AA) Similarity theorem.

This trick only works with triangles. It partially works with rectangles; however, we would need to be sure that the corresponding sides were proportional as well. There isn't a 100% guarantee that any two rectangles are similar.

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Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a

jeka57 [31]

Answer:

$\\ \gamma= \frac{a\cdot b}{b\cdot b}$

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if $b \neq 0$ . Recall that given two vectors a,b a⊥ b if and only if $a\cdot b =0$ where $\cdot$ is the dot product defined in $\mathbb{R}^n$ . Suposse that $b\neq 0$ . We want to find γ such that $(a-\gamma b)\cdot b=0$ . Given that the dot product can be distributed and that it is linear, the following equation is obtained