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Rasek [7]
3 years ago
7

Which quantity identifies an element?

Chemistry
2 answers:
aliina [53]3 years ago
6 0
Atomic number identifies an element. Atomic number is the  number of protons in the atom of an element, which is different for every element.
vodka [1.7K]3 years ago
4 0

Answer is (1) - atomic number.

Atomic number is unique for an element. The elements in periodic table are organized according to the atomic number of elements. Another thing is atomic number is equal to number of protons of the element.

Mass number can be defined as the sum of proton number and neutron number. Although proton number is same for the atoms of same element, the neutron number can be varied. The atoms which has same atomic number but have different number of neutrons are called isotopes. Hence, mass number not enough for the identification of elements.

Only the neutron number is also not enough for the identification of elements. But if you have both mass number and the neutron number, then you can find atomic number by using <em>mass number = proton number + neutron number</em> equation. Then you can identify the element.

If you have total number of electrons of the element when it is in its neutral state you can identify the element because at neutral state <em>number of electrons = number of protons (atomic number). </em>But if only the valence electrons are given then you cannot find the element exactly<em> because usually all elements in certain group have same number of valence electrons.</em>

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Answer:

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What subatomic particle is specifically responsible for combining the atoms together to form a new substance?
julsineya [31]
Electron 

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g (2pts) A 10x transfer buffer solution is 250mM Tris and 1.92M glycine. Buffers are always used at 1x concentration in the lab
uranmaximum [27]

Answer:

The explanation according to the given question is summarized below.

Explanation:

Given:

Tris,

= 250 mM

Glycine,

= 1.92 M

According to the solution,

For the dilution pf 10X to 1X buffer, we get

= 1 \ ml \ of \ 10X \ buffer +9 \ ml \ of \ distilled \ water

= 10

i.e.,

⇒ 10X \ to \ 1X=1:10 \ dilution

Now,

⇒ 10X (250 \ mM\ Tris \ HCl, 1.92M\ Glycine, and\ 1 \ percent (\frac{w}{v} ) SDS) ---->1X(25 \ mM \ Tris \ HCl,0.193 M\ Glycine, and \ 0.1 \ percent(\frac{w}{v} )SDS)

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