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777dan777 [17]
3 years ago
8

What is the mass (in grams) of 169 mole of CF4

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
3 0
The answer will depend on the number of significant figures you want in your answer, so I can't give you a solid answer, but the process is still the same: you convert from grams to moles by using the molar mass.

You can calculate the molar mass of carbon tetrafluoride from the periodic table, by adding the molar mass of 1 atom of C and 4 atoms of F. Round the total molar mass to the appropriate number and multiply 169 moles by the molar mass you just calculated.

Hope this helps!
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Which of the following would have the largest pKa?
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Answer:

CH3CH2NH3+/CH3CH2NH2 would have the largest pKa

Explanation:

To answer this question we must know Kb of CH3CH2NH2 is 5.6x10⁻⁴, and for C6H5NH2 is 4.0x10⁻¹⁰. And the CH3CH2NH3+ and C6H5NH3+ are related with these substances because are their conjugate base. That means:

pKa of  CH3CH2NH3+ =  CH3CH2NH2;  C6H5NH3+ =  C6H5NH2

Also, Kw / Kb = Ka

Thus:

pKa of CH3CH2NH3+/CH3CH2NH2 is:

Kw / kb = Ka = 1.79x10⁻¹¹

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pKa of C6H5NH3+/ C6H5NH2 is:

Kw / kb = Ka = 2.5x10⁻⁵

-log Ka = pKa

pKa = 4.6

That means CH3CH2NH3+/CH3CH2NH2 would have the largest pKa

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Answer:- The formula Ca(NO_3)_2 tells us that one formula unit of this compound is composed of one calcium atom, two nitrogen atoms, and six oxygen atoms.

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When we have subscripts inside and outside the parenthesis then they are multiplied and the outside subscript is considered for all the atoms present inside the parenthesis.

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