Answer:
The angular frequency of the block is ω = 5.64 rad/s
Explanation:
The speed of the block v = rω where r = amplitude of the oscillation and ω = angular frequency of the oscillation.
Now ω = v/r since v = speed of the block = 62 cm/s and r = the amplitude of the oscillation = 11 cm.
The angular frequency of the oscillation ω is
ω = v/r
ω = 62 cm/s ÷ 11 cm
ω = 5.64 rad/s
So, the angular frequency of the block is ω = 5.64 rad/s
Answer:
e = Δφ / Δt induced emf is proportional to enclosed flux
Also φ = B * A flux is proportional to area and enclosed field
If the induced emf e increases with time than the flux and hence the magnetic field is increasing with time (replace B with G)
Since e = ΔG * A / Δt if e is linear then G must also be linear and be proportional to the time
Answer:
use the formula for option B ( d/t = s )
and
look at the graph representation to explain