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sladkih [1.3K]
3 years ago
15

Two small objects, with masses m and m, are originally a distance r apart, and the gravitational force on each one has magnitude

f. the second object has its mass changed to 2m, and the distance is changed to r/4. what is the magnitude of the new gravitational force?
Physics
2 answers:
elena-s [515]3 years ago
6 0
32f. That's because the force is directly proportional to the product of the masses and inversely proportional to the square of the distance. So you get 2•(1/1/4)^2=2•16=32
WINSTONCH [101]3 years ago
5 0

Answer:

New gravitational force, F' = 32 F

Explanation:

The gravitational force acting on two objects that are separated by a distance r between them is given by :

F=G\dfrac{mM}{r^2}

m is the mass of object 1

M is the mass of object 2

Now, the second object has its mass changed to 2m, and distance is changed to r/4. So, the gravitational force becomes :

F'=G\dfrac{m\times 2M}{(r/4)^2}

F'=32\times \dfrac{GmM}{r^2}

F'=32\times F

So, the magnitude of the new gravitational force is 32 times the previous force. Hence, this is the required solution.

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is reflected back into the region of higher index

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\theta_2 is the angle of refraction (in the second medium)

Let's now consider a situation in which

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sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

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In a device like the one shown below, the cylinder is allowed to fall a distance of 300 m. As a result, the temperature of the w
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8 0
3 years ago
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