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sladkih [1.3K]
3 years ago
15

Two small objects, with masses m and m, are originally a distance r apart, and the gravitational force on each one has magnitude

f. the second object has its mass changed to 2m, and the distance is changed to r/4. what is the magnitude of the new gravitational force?
Physics
2 answers:
elena-s [515]3 years ago
6 0
32f. That's because the force is directly proportional to the product of the masses and inversely proportional to the square of the distance. So you get 2•(1/1/4)^2=2•16=32
WINSTONCH [101]3 years ago
5 0

Answer:

New gravitational force, F' = 32 F

Explanation:

The gravitational force acting on two objects that are separated by a distance r between them is given by :

F=G\dfrac{mM}{r^2}

m is the mass of object 1

M is the mass of object 2

Now, the second object has its mass changed to 2m, and distance is changed to r/4. So, the gravitational force becomes :

F'=G\dfrac{m\times 2M}{(r/4)^2}

F'=32\times \dfrac{GmM}{r^2}

F'=32\times F

So, the magnitude of the new gravitational force is 32 times the previous force. Hence, this is the required solution.

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Vlada [557]

Answer:

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Explanation:

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With the initial data let's look for the ratio k / m

The angular velocity is related to the frequency and period

           w = 2π f = 2π / T

            2π / T = √ k / m

            k₀ / m₀ = (2π / T)²

            k₀ / m₀ = (2π / 3.0)²

            k₀ / m₀ = 4.3865

The period on the new planet is

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In this case the amounts are

           m = 6 m₀

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We replace

            T = 2π√6m₀ / 10k₀

            T = 2π √6/10 √m₀ / k₀

            T = 2π √ 0.6  √1 / 4.3865

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Given :

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