Electrolysis of a dilute solution of aqueous sodium chloride results in the cathode product

For a charged particle accelerated by an electric field, the kinetic energy gained by the particle is equal to the decrease in electric potential energy of the particle; therefore:

$K_f-K_i = -q\Delta V$

where

$K_f$ is the final kinetic energy

$K_i$ is the initial kinetic energy

q is the charge of the particle

$\Delta V$ is the potential difference

In this problem,

$q=-1.6\cdot 10^{-19}C$ is the charge of the electron

$\Delta V=-500 V-(-1000 V)=500 V$

The electron starts from rest, so its initial kinetic energy is

$K_i=0$

Therefore,

$K_f=-(-1.6\cdot 10^{-19})(500)=8\cdot 10^{-17}J$

We can write the final kinetic energy of the electron as

$K_f=\frac{1}{2}mv^2$

where

$m=9.11\cdot 10^{-31} kg$ is the electron mass

v is the final speed

And solving for v,

$v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(8\cdot 10^{-17})}{9.11\cdot 10^{-31}}}=1.33\cdot 10^7 m/s$

5 0

2 years ago

A sample of helium gas at 27.0 °C and 3.60 atm pressure is cooled in the same container to a temperature of -73.0 °C. What is th

trasher [3.6K]

Answer: The new pressure, if volume and amount of gas do not change is 2.40 atm

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=3.60atm\\T_1=27^0C=(27+273)K=300K\\P_2=?\\T_2=-73.0^0C=(273-73)=200K$

Putting values in above equation, we get:

$\frac{3.60}{300K}=\frac{P_2}{200K}\\\\P_2=2.40atm$

Thus the new pressure, if volume and amount of gas do not change is 2.40 atm

5 0

3 years ago

How much heat is absorbed when 63.7 g H2O(l) at 100 degrees Celsius and 101.3kPa is converted to steam at 100

Alona [7]

Answer:

Q = 143,921 J = 143.9 kJ.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:

$Q=m*\Delta _{vap}H$

Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:

$Q=63.7g*2259.36J/g\\\\Q=143,921J=143.9kJ$

Regards!

3 0

2 years ago