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4 years ago

Cube edge length is 3.23 all sides what is the volume

Chemistry

1 answer:

atroni [7]4 years ago

7 0

V=l.w.h
since the sides of a cube are equal it will be 3.23^3=33.69827

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What is the boiling point of water when the external pressure is 187.5 mmhg?

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i believe the answer is 65°c

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4 years ago

A motorcycle travels 833 meters in 13 seconds. What is its average speed?

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3 years ago

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Calculate how many grams of hydrogen can be burned if 40. liters of oxygen at 200. k and 1.0 atm. show work pls.

Wittaler [7]

The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.

<h3>How do we calculate grams from moles?</h3>

Grams (W) of any substance will be calculated by using their moles (n) through the following equation:

n = W/M, where

M = molar mass

And moles of the gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure = 1atm

V = volume = 40L

n = moles = ?

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature = 200K

On putting these values on the above equation, we get

n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles

Now grams of hydrogen gas will be calculated by using the first equation as:

W = (2.44mol)(2g/mol) = 4.88g

Hence required mass of hydrogen gas is 4.88g.

To know more about ideal gas equation, visit the below link:

brainly.com/question/15046679

#SPJ1

7 0

3 years ago

Non examples of chemical formulas

Bezzdna [24]

Answer:

1+2 = 12

Explanation:

this is a math equation, not a chemical formula

6 0

3 years ago

an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem

OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

$P\cdot V = n\cdot R\cdot T$ ,

$\displaystyle V = \frac{n\cdot R\cdot T}{P}$ .

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of moles of particles in this gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of $R$ will be $8.314$ if $P$ , $V$ , and $T$ are in SI units. Convert these values to SI units:

$P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa$ ;
$V$ shall be in cubic meters, $\rm m^{3}$ ;
$T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K$ .

Apply the ideal gas law:

$\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}$ .

4 0

4 years ago