Answer: See explanation
Explanation:
From the information given, we are informed that an instrument rated pilot is planning a flight under IFR on July 10, this year.
It should be noted that before conducting the flight, the pilot must have performed and logged the prescribed tasks and repetitions that are required for instrument currency no earlier than January, 10 for the year.
Answer:
B.The slinky descriptions of motion are switched.
Explanation:
First of all, let's define the two types of wave:
- Transverse wave: in a transverse wave, the oscillation of the wave occurs in a direction perpendicular to the direction of propagation of the wave. An example of transverse wave are electromagnetic waves.
- Longitudinal wave: in a longitudinal wave, the oscillation of the wave occurs in a direction parallel to the direction of propagation of the wave. An example of longitudinal wave are sound waves.
According to these definitions, we notice that the following descriptions of motion must be switched:
- "Like moving a spring up and down" --> this better describes a transverse wave, because the motion up/down is perpendicular to the direction of the spring
- "Like moving a spring back and forth" --> this better describes a longitudinal wave, because the back/forth motion is parallel to the direction of the spring
Answer:
The mass of the asteroids is 0.000334896182184 times the mass of the Earth.
39929.4542466 m
Explanation:
Total mass of the asteroids
= Mass of Earth = 
The ratio is
The mass of the asteroids is 0.000334896182184 times the mass of the Earth.
Volume is given by
The diameter is 39929.4542466 m
Answer:
1.74 m/s
Explanation:
From the question, we are given that the mass of the an object, m1= 2.7 kilogram(kg) and the mass of the can,m(can) is 0.72 Kilogram (kg). The velocity of the mass of an object(m1) , V1 is 1.1 metre per seconds(m/s) and the velocity of the mass of can[m(can)], V(can) is unknown- this is what we are to find.
Therefore, using the formula below, we can calculate the speed of the can, V(can);
===> Mass of object,m1 × velocity of object, V1 = mass of the can[m(can)] × velocity is of the can[V(can)].----------------------------------------------------(1).
Since the question says the collision was elastic, we use the formula below
Slotting in the given values into the equation (1) above, we have;
1/2×M1×V^2(initial velocity of the first object) + 1/2 ×M(can)×V^2(final velocy of the first object)= 1/2 × M1 × V^2 m( initial velocity of the first object).
Therefore, final velocity of the can= 2M1V1/M1+M2.
==> 2×2.7×1.1/ 2.7 + 0.72.
The velocity of the can after collision = 1.74 m/s
